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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Ln(r e^(i?)) = ln r + i(? + 2pn) - for all integers n






2. Multiply moduli and add arguments






3. Written as fractions - terminating + repeating decimals






4. All numbers






5. We see in this way that the distance between two points z and w in the complex plane is






6. A number that can be expressed as a fraction p/q where q is not equal to 0.






7. R?¹(cos? - isin?)






8. 3






9. 1






10. 2nd. Rule of Complex Arithmetic

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11. y / r






12. 2ib






13. Not on the numberline






14. When you add two complex numbers a + bi and c + di - you get the sum of the real parts and the sum of the imaginary parts: (a + bi) + (c + di) = (a + c) + (b + d)i






15. ? = -tan?






16. Solutions to zn = 1 - |z| = 1 - z = e^(i?) - e^(in?) = 1






17. When two complex numbers are divided.






18. A complex number may be taken to the power of another complex number.






19. (a + bi) = (c + bi) =






20. Formula: z1 · z2 = (a + bi)(c + di) = ac +adi +cbi +bdi² = (ac - bd) + (ad +cb)i - when you multiply a complex number by its conjugate - you get a real number.






21. Any number not rational






22. Has exactly n roots by the fundamental theorem of algebra






23. To simplify a complex fraction






24. The product of an imaginary number and its conjugate is






25. A + bi






26. Given (4-2i) the complex conjugate would be (4+2i)






27. No i






28. 4th. Rule of Complex Arithmetic






29. I






30. (2+i)(2i-3) you would use the foil methom which is first outter inner last. (2x2i)(2x-3)(ix2i^2)(ix(-3) =i-8






31. Every complex number has the 'Standard Form':






32. Imaginary number

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33. R^2 = x






34. z1z2* / |z2|²






35. Derives z = a+bi






36. I






37. 1. i^2 = -1 2. Every complex number has the 'Standard Form': a + bi for some real a and b. 3. For real a and b - a + bi = 0 if and only if a = b = 0 4. (a + bi) = (c + bi) = (a + c) + ( b + d)i 5. (a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc






38. (a + bi)(c + bi) =






39. xpressions such as ``the complex number z'' - and ``the point z'' are now






40. To prove that number field every algebraic equation in z with complex coefficients has a solution we need

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41. To simplify the square root of a negative number






42. (e^(-y) - e^(y)) / 2i = i sinh y






43. A + bi = z1 c + di = z2 - addition: z1 + z2 = (a + bi) + (c + di) = (a + c) + (b + d)i subtraction: z1 - z2 = (a - c) + (b - d)i






44. The field of all rational and irrational numbers.






45. E^(i?) = cos? + isin? ; e^(ip) + 1 = 0

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46. The modulus of the complex number z= a + ib now can be interpreted as






47. Root negative - has letter i






48. A² + b² - real and non negative






49. When you multiply two complex numbers a + bi and c + di FOIL the terms: (a + bi)(c + di) = (ac - bd) + (ad + bc)i






50. What about dividing one complex number by another? Is the result another complex number? Let's ask the question in another way. If you are given four real numbers a -b -c and d - can you find two other real numbers x and y so that