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Test your basic knowledge |
CLEP General Mathematics: Complex Numbers
Start Test
Study First
Subjects
:
clep
,
math
Instructions:
Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. If z= a+bi is a complex number and a and b are real - we say that a is the real part of z and that b is the imaginary part of z
Real and Imaginary Parts
cos iy
Subfield
(cos? +isin?)n
2. One of the numbers ... --2 --1 - 0 - 1 - 2 - ....
Complex Number
Integers
non-integers
Irrational Number
3. When two complex numbers are multipiled together.
Complex Multiplication
imaginary
standard form of complex numbers
i^1
4. 1
For real a and b - a + bi = 0 if and only if a = b = 0
ln z
interchangeable
i²
5. 1. i^2 = -1 2. Every complex number has the 'Standard Form': a + bi for some real a and b. 3. For real a and b - a + bi = 0 if and only if a = b = 0 4. (a + bi) = (c + bi) = (a + c) + ( b + d)i 5. (a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc
Rules of Complex Arithmetic
We say that c+di and c-di are complex conjugates.
multiply the numerator and the denominator by the complex conjugate of the denominator.
non-integers
6. Written as fractions - terminating + repeating decimals
rational
point of inflection
adding complex numbers
cos iy
7. The modulus of the complex number z= a + ib now can be interpreted as
subtracting complex numbers
the distance from z to the origin in the complex plane
Complex Subtraction
Complex Conjugate
8. We can also think of the point z= a+ ib as
the vector (a -b)
can't get out of the complex numbers by adding (or subtracting) or multiplying two
Polar Coordinates - Multiplication
standard form of complex numbers
9. To simplify the square root of a negative number
Polar Coordinates - Multiplication by i
z1 ^ (z2)
you write the square root as the product of square roots and simplify: v(-a) = v(-1)v(a) = iv(a)
imaginary
10. Like pi
e^(ln z)
Euler's Formula
transcendental
Rules of Complex Arithmetic
11. A subset within a field.
you write the square root as the product of square roots and simplify: v(-a) = v(-1)v(a) = iv(a)
transcendental
Subfield
sin z
12. I^26/4= i^24 x i^2 =-1 so u divide the number by 4 and whatevers left over is the number that its equal to.
v(-1)
radicals
Polar Coordinates - z?¹
How to find any Power
13. Formula: z1 · z2 = (a + bi)(c + di) = ac +adi +cbi +bdi² = (ac - bd) + (ad +cb)i - when you multiply a complex number by its conjugate - you get a real number.
Complex Numbers: Multiply
z1 / z2
sin z
Irrational Number
14. Derives z = a+bi
interchangeable
Euler Formula
Polar Coordinates - Arg(z*)
z + z*
15. E ^ (z2 ln z1)
z1 ^ (z2)
Polar Coordinates - r
radicals
Real and Imaginary Parts
16. We see in this way that the distance between two points z and w in the complex plane is
The Complex Numbers
|z-w|
i^0
(cos? +isin?)n
17. A + bi
you write the square root as the product of square roots and simplify: v(-a) = v(-1)v(a) = iv(a)
How to find any Power
standard form of complex numbers
the vector (a -b)
18. A² + b² - real and non negative
zz*
conjugate pairs
e^(ln z)
0 if and only if a = b = 0
19. Ln(r e^(i?)) = ln r + i(? + 2pn) - for all integers n
ln z
(a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc) + (bc + ad)i
z - z*
cosh²y - sinh²y
20. z1z2* / |z2|²
i²
complex numbers
'i'
z1 / z2
21. R?¹(cos? - isin?)
Polar Coordinates - cos?
Polar Coordinates - z?¹
Imaginary Unit
subtracting complex numbers
22. (e^(-y) - e^(y)) / 2i = i sinh y
conjugate pairs
i^2 = -1
sin iy
Imaginary Numbers
23. All the powers of i can be written as
real
z1 / z2
four different numbers: i - -i - 1 - and -1.
i^2
24. 2ib
Real Numbers
cos iy
Field
z - z*
25. 5th. Rule of Complex Arithmetic
radicals
Polar Coordinates - cos?
(a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc) + (bc + ad)i
|z| = mod(z)
26. Has the opposite sign of a complex number; the conjugate of a + bi is a - bi
sin z
complex
How to solve (2i+3)/(9-i)
conjugate
27. To prove that number field every algebraic equation in z with complex coefficients has a solution we need
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28. Divide moduli and subtract arguments
Integers
Field
Polar Coordinates - Division
We say that c+di and c-di are complex conjugates.
29. Any set of elements that satisfies the field axioms for both addition and multiplication and is a commutative division algebra.
Complex Number
Field
De Moivre's Theorem
adding complex numbers
30. I
|z| = mod(z)
cosh²y - sinh²y
(a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc) + (bc + ad)i
i^1
31. 1
i^4
How to solve (2i+3)/(9-i)
Rules of Complex Arithmetic
v(-1)
32. The field of all rational and irrational numbers.
Euler Formula
Complex Numbers: Add & subtract
Real Numbers
Real and Imaginary Parts
33. V(x² + y²) = |z|
Polar Coordinates - r
subtracting complex numbers
Rules of Complex Arithmetic
Real and Imaginary Parts
34. Multiply moduli and add arguments
Real Numbers
Polar Coordinates - Multiplication
cosh²y - sinh²y
How to find any Power
35. When two complex numbers are subtracted from one another.
a + bi for some real a and b.
Subfield
Complex Subtraction
Real and Imaginary Parts
36. When two complex numbers are divided.
interchangeable
irrational
Any polynomial O(xn) - (n > 0)
Complex Division
37. 2a
Imaginary Numbers
z + z*
point of inflection
interchangeable
38. 3rd. Rule of Complex Arithmetic
For real a and b - a + bi = 0 if and only if a = b = 0
the vector (a -b)
Imaginary Unit
Field
39. E^(ln r) e^(i?) e^(2pin)
e^(ln z)
|z-w|
z1 / z2
The Complex Numbers
40. xpressions such as ``the complex number z'' - and ``the point z'' are now
multiplying complex numbers
natural
zz*
interchangeable
41. Every complex number has the 'Standard Form':
cos iy
a + bi for some real a and b.
transcendental
conjugate pairs
42. Cos n? + i sin n? (for all n integers)
|z-w|
radicals
(cos? +isin?)n
Affix
43. When you subtract two complex numbers a + bi and c + di - you get the difference of the real parts and the difference of the imaginary parts: (a + bi) - (c + di) = (a - c) + (b - d)i
rational
Polar Coordinates - z?¹
real
subtracting complex numbers
44. All numbers
complex
i^2 = -1
the vector (a -b)
(a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc) + (bc + ad)i
45. A complex number may be taken to the power of another complex number.
(a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc) + (bc + ad)i
Complex Exponentiation
non-integers
Complex Number Formula
46. To simplify a complex fraction
Any polynomial O(xn) - (n > 0)
Polar Coordinates - Division
transcendental
multiply the numerator and the denominator by the complex conjugate of the denominator.
47. It is an amazing fact that by adjoining the imaginary unit i to the real numbers we obtain a complete number field called
e^(ln z)
The Complex Numbers
(a + c) + ( b + d)i
i^2 = -1
48. y / r
Polar Coordinates - Multiplication
Complex Conjugate
Polar Coordinates - sin?
i^2 = -1
49. ½(e^(-y) +e^(y)) = cosh y
Polar Coordinates - sin?
rational
complex
cos iy
50. The reals are just the
Liouville's Theorem -
Complex Conjugate
conjugate pairs
x-axis in the complex plane