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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Have radical






2. x + iy = r(cos? + isin?) = re^(i?)






3. A complex number and its conjugate






4. V(zz*) = v(a² + b²)






5. Starts at 1 - does not include 0






6. Equivalent to an Imaginary Unit.






7. When two complex numbers are divided.






8. Every complex number has the 'Standard Form':






9. Multiply moduli and add arguments






10. (a + bi)(c + bi) =






11. 1






12. The modulus of the complex number z= a + ib now can be interpreted as






13. zn = (cos? + isin?)n = cosn? + isinn? - For all integers n

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14. I^26/4= i^24 x i^2 =-1 so u divide the number by 4 and whatevers left over is the number that its equal to.






15. ? = -tan?






16. z1z2* / |z2|²






17. Cos n? + i sin n? (for all n integers)






18. ½(e^(-y) +e^(y)) = cosh y






19. 2ib






20. Divide moduli and subtract arguments






21. 5th. Rule of Complex Arithmetic






22. Notice that rules 4 and 5 state that we complex numbers together - we can divide by c + di if c and d are not both zero. But there is a much easier way to do division.

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23. A complex number may be taken to the power of another complex number.






24. 1






25. V(x² + y²) = |z|






26. All the powers of i can be written as






27. For real a and b - a + bi =






28. A plot of complex numbers as points.






29. The square root of -1.






30. If z= a+bi is a complex number and a and b are real - we say that a is the real part of z and that b is the imaginary part of z






31. Root negative - has letter i






32. (e^(iz) - e^(-iz)) / 2i






33. (2i+3)/(9-i)for the denominator you multiply by the conjugate and what u do to the bottom u have to do to the top then you distribute the bottom then the top then add like terms then you simplify. 21i+25/17






34. The reals are just the






35. It is an amazing fact that by adjoining the imaginary unit i to the real numbers we obtain a complete number field called






36. When two complex numbers are added together.






37. Numbers on a numberline






38. To prove that number field every algebraic equation in z with complex coefficients has a solution we need

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39. To simplify a complex fraction






40. Formula: z1 · z2 = (a + bi)(c + di) = ac +adi +cbi +bdi² = (ac - bd) + (ad +cb)i - when you multiply a complex number by its conjugate - you get a real number.






41. A + bi






42. The complex number z representing a+bi.






43. Imaginary number

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44. I






45. A + bi = z1 c + di = z2 - addition: z1 + z2 = (a + bi) + (c + di) = (a + c) + (b + d)i subtraction: z1 - z2 = (a - c) + (b - d)i






46. Real and imaginary numbers






47. We consider the a real number x to be the complex number x+ 0i and in this way we can think of the real numbers as a subset of






48. When you subtract two complex numbers a + bi and c + di - you get the difference of the real parts and the difference of the imaginary parts: (a + bi) - (c + di) = (a - c) + (b - d)i






49. (2-3i)-(4+6i)you would distribute the negitive and combine your like terms and your answer is -2-9i






50. Given (4-2i) the complex conjugate would be (4+2i)