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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. A number that cannot be expressed as a fraction for any integer.






2. The modulus of the complex number z= a + ib now can be interpreted as






3. No i






4. (a + bi)(c + bi) =






5. 1






6. x / r






7. Ln(r e^(i?)) = ln r + i(? + 2pn) - for all integers n






8. 1. i^2 = -1 2. Every complex number has the 'Standard Form': a + bi for some real a and b. 3. For real a and b - a + bi = 0 if and only if a = b = 0 4. (a + bi) = (c + bi) = (a + c) + ( b + d)i 5. (a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc






9. Imaginary number

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10. We can also think of the point z= a+ ib as






11. When you multiply two complex numbers a + bi and c + di FOIL the terms: (a + bi)(c + di) = (ac - bd) + (ad + bc)i






12. Where the curvature of the graph changes






13. zn = (cos? + isin?)n = cosn? + isinn? - For all integers n

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14. ½(e^(-y) +e^(y)) = cosh y






15. (e^(-y) - e^(y)) / 2i = i sinh y






16. E ^ (z2 ln z1)






17. Not on the numberline






18. 1st. Rule of Complex Arithmetic






19. In the same way that we think of real numbers as being points on a line - it is natural to identify a complex number z=a+ib with the point (a -b) in the cartesian plane.






20. Numbers on a numberline






21. (e^(iz) - e^(-iz)) / 2i






22. When two complex numbers are added together.






23. What about dividing one complex number by another? Is the result another complex number? Let's ask the question in another way. If you are given four real numbers a -b -c and d - can you find two other real numbers x and y so that






24. (2-3i)-(4+6i)you would distribute the negitive and combine your like terms and your answer is -2-9i






25. V(x² + y²) = |z|






26. xpressions such as ``the complex number z'' - and ``the point z'' are now






27. The reals are just the






28. Derives z = a+bi






29. Have radical






30. 2ib






31. Written as fractions - terminating + repeating decimals






32. The square root of -1.






33. 1






34. (2i+3)/(9-i)for the denominator you multiply by the conjugate and what u do to the bottom u have to do to the top then you distribute the bottom then the top then add like terms then you simplify. 21i+25/17






35. Has the opposite sign of a complex number; the conjugate of a + bi is a - bi






36. Formula: z1 · z2 = (a + bi)(c + di) = ac +adi +cbi +bdi² = (ac - bd) + (ad +cb)i - when you multiply a complex number by its conjugate - you get a real number.






37. 1






38. A+bi






39. Cos n? + i sin n? (for all n integers)






40. For real a and b - a + bi =






41. x + iy = r(cos? + isin?) = re^(i?)






42. One of the numbers ... --2 --1 - 0 - 1 - 2 - ....






43. When you subtract two complex numbers a + bi and c + di - you get the difference of the real parts and the difference of the imaginary parts: (a + bi) - (c + di) = (a - c) + (b - d)i






44. z1z2* / |z2|²






45. V(zz*) = v(a² + b²)






46. Any set of elements that satisfies the field axioms for both addition and multiplication and is a commutative division algebra.






47. A + bi = z1 c + di = z2 - addition: z1 + z2 = (a + bi) + (c + di) = (a + c) + (b + d)i subtraction: z1 - z2 = (a - c) + (b - d)i






48. A complex number may be taken to the power of another complex number.






49. (a + bi) = (c + bi) =






50. A subset within a field.