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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. z1z2* / |z2|²






2. (2+i)(2i-3) you would use the foil methom which is first outter inner last. (2x2i)(2x-3)(ix2i^2)(ix(-3) =i-8






3. 2nd. Rule of Complex Arithmetic

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4. A subset within a field.






5. 4th. Rule of Complex Arithmetic






6. Solutions to zn = 1 - |z| = 1 - z = e^(i?) - e^(in?) = 1






7. The complex number z representing a+bi.






8. I^26/4= i^24 x i^2 =-1 so u divide the number by 4 and whatevers left over is the number that its equal to.






9. I = imaginary unit - i² = -1 or i = v-1






10. Multiply moduli and add arguments






11. Imaginary number

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12. Numbers on a numberline






13. The square root of -1.






14. (e^(iz) - e^(-iz)) / 2i






15. xpressions such as ``the complex number z'' - and ``the point z'' are now






16. Where the curvature of the graph changes






17. When two complex numbers are added together.






18. 1






19. To prove that number field every algebraic equation in z with complex coefficients has a solution we need

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20. I






21. Notice that rules 4 and 5 state that we complex numbers together - we can divide by c + di if c and d are not both zero. But there is a much easier way to do division.

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22. If z= a+bi is a complex number and a and b are real - we say that a is the real part of z and that b is the imaginary part of z






23. (a + bi)(c + bi) =






24. (2i+3)/(9-i)for the denominator you multiply by the conjugate and what u do to the bottom u have to do to the top then you distribute the bottom then the top then add like terms then you simplify. 21i+25/17






25. 1. i^2 = -1 2. Every complex number has the 'Standard Form': a + bi for some real a and b. 3. For real a and b - a + bi = 0 if and only if a = b = 0 4. (a + bi) = (c + bi) = (a + c) + ( b + d)i 5. (a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc






26. y / r






27. ½(e^(iz) + e^(-iz))






28. All the powers of i can be written as






29. When you multiply two complex numbers a + bi and c + di FOIL the terms: (a + bi)(c + di) = (ac - bd) + (ad + bc)i






30. It is an amazing fact that by adjoining the imaginary unit i to the real numbers we obtain a complete number field called






31. R?¹(cos? - isin?)






32. Ln(r e^(i?)) = ln r + i(? + 2pn) - for all integers n






33. Real and imaginary numbers






34. 1






35. E ^ (z2 ln z1)






36. Every complex number has the 'Standard Form':






37. Like pi






38. For real a and b - a + bi =






39. A² + b² - real and non negative






40. The product of an imaginary number and its conjugate is






41. The reals are just the






42. (2-3i)-(4+6i)you would distribute the negitive and combine your like terms and your answer is -2-9i






43. When you add two complex numbers a + bi and c + di - you get the sum of the real parts and the sum of the imaginary parts: (a + bi) + (c + di) = (a + c) + (b + d)i






44. What about dividing one complex number by another? Is the result another complex number? Let's ask the question in another way. If you are given four real numbers a -b -c and d - can you find two other real numbers x and y so that






45. Equivalent to an Imaginary Unit.






46. All numbers






47. Cos n? + i sin n? (for all n integers)






48. The modulus of the complex number z= a + ib now can be interpreted as






49. I^2 =






50. 3rd. Rule of Complex Arithmetic