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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Root negative - has letter i






2. We see in this way that the distance between two points z and w in the complex plane is






3. (e^(iz) - e^(-iz)) / 2i






4. E^(ln r) e^(i?) e^(2pin)






5. A number that cannot be expressed as a fraction for any integer.






6. A plot of complex numbers as points.






7. ½(e^(iz) + e^(-iz))






8. zn = (cos? + isin?)n = cosn? + isinn? - For all integers n

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9. A² + b² - real and non negative






10. 1






11. To simplify a complex fraction






12. x + iy = r(cos? + isin?) = re^(i?)






13. The complex number z representing a+bi.






14. The square root of -1.






15. The reals are just the






16. Any number not rational






17. V(zz*) = v(a² + b²)






18. V(x² + y²) = |z|






19. To simplify the square root of a negative number






20. y / r






21. 1






22. In this amazing number field every algebraic equation in z with complex coefficients






23. 1






24. 3






25. Like pi






26. Notice that rules 4 and 5 state that we complex numbers together - we can divide by c + di if c and d are not both zero. But there is a much easier way to do division.

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27. Given (4-2i) the complex conjugate would be (4+2i)






28. Not on the numberline






29. A + bi = z1 c + di = z2 - addition: z1 + z2 = (a + bi) + (c + di) = (a + c) + (b + d)i subtraction: z1 - z2 = (a - c) + (b - d)i






30. Divide moduli and subtract arguments






31. Where the curvature of the graph changes






32. Equivalent to an Imaginary Unit.






33. A subset within a field.






34. We can also think of the point z= a+ ib as






35. To prove that number field every algebraic equation in z with complex coefficients has a solution we need

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36. We consider the a real number x to be the complex number x+ 0i and in this way we can think of the real numbers as a subset of






37. When two complex numbers are divided.






38. (2-3i)-(4+6i)you would distribute the negitive and combine your like terms and your answer is -2-9i






39. For real a and b - a + bi =






40. Written as fractions - terminating + repeating decimals






41. Multiply moduli and add arguments






42. All numbers






43. I






44. Derives z = a+bi






45. E^(i?) = cos? + isin? ; e^(ip) + 1 = 0

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46. Has exactly n roots by the fundamental theorem of algebra






47. (2+i)(2i-3) you would use the foil methom which is first outter inner last. (2x2i)(2x-3)(ix2i^2)(ix(-3) =i-8






48. A+bi






49. R?¹(cos? - isin?)






50. I