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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. ½(e^(-y) +e^(y)) = cosh y






2. Not on the numberline






3. I^26/4= i^24 x i^2 =-1 so u divide the number by 4 and whatevers left over is the number that its equal to.






4. To simplify the square root of a negative number






5. 1






6. When you subtract two complex numbers a + bi and c + di - you get the difference of the real parts and the difference of the imaginary parts: (a + bi) - (c + di) = (a - c) + (b - d)i






7. 5th. Rule of Complex Arithmetic






8. 3






9. In this amazing number field every algebraic equation in z with complex coefficients






10. ½(e^(iz) + e^(-iz))






11. When you add two complex numbers a + bi and c + di - you get the sum of the real parts and the sum of the imaginary parts: (a + bi) + (c + di) = (a + c) + (b + d)i






12. E^(i?) = cos? + isin? ; e^(ip) + 1 = 0

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13. A subset within a field.






14. zn = (cos? + isin?)n = cosn? + isinn? - For all integers n

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15. Multiply moduli and add arguments






16. All the powers of i can be written as






17. Like pi






18. Complex Plane = i - Use the distance formula to determine the point's distance from zero - or - the absolute value.






19. xpressions such as ``the complex number z'' - and ``the point z'' are now






20. 2ib






21. A + bi






22. Divide moduli and subtract arguments






23. Written as fractions - terminating + repeating decimals






24. All numbers






25. Ln(r e^(i?)) = ln r + i(? + 2pn) - for all integers n






26. It is an amazing fact that by adjoining the imaginary unit i to the real numbers we obtain a complete number field called






27. 1






28. R?¹(cos? - isin?)






29. One of the numbers ... --2 --1 - 0 - 1 - 2 - ....






30. (e^(-y) - e^(y)) / 2i = i sinh y






31. Has exactly n roots by the fundamental theorem of algebra






32. (e^(iz) - e^(-iz)) / 2i






33. For real a and b - a + bi =






34. (2-3i)-(4+6i)you would distribute the negitive and combine your like terms and your answer is -2-9i






35. In the same way that we think of real numbers as being points on a line - it is natural to identify a complex number z=a+ib with the point (a -b) in the cartesian plane.






36. 2nd. Rule of Complex Arithmetic

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37. When two complex numbers are subtracted from one another.






38. 1st. Rule of Complex Arithmetic






39. What about dividing one complex number by another? Is the result another complex number? Let's ask the question in another way. If you are given four real numbers a -b -c and d - can you find two other real numbers x and y so that






40. (a + bi) = (c + bi) =






41. 1






42. A plot of complex numbers as points.






43. I






44. We can also think of the point z= a+ ib as






45. 2a






46. Every complex number has the 'Standard Form':






47. Cos n? + i sin n? (for all n integers)






48. (2+i)(2i-3) you would use the foil methom which is first outter inner last. (2x2i)(2x-3)(ix2i^2)(ix(-3) =i-8






49. We see in this way that the distance between two points z and w in the complex plane is






50. Given (4-2i) the complex conjugate would be (4+2i)







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