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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. A + bi = z1 c + di = z2 - addition: z1 + z2 = (a + bi) + (c + di) = (a + c) + (b + d)i subtraction: z1 - z2 = (a - c) + (b - d)i






2. Cos n? + i sin n? (for all n integers)






3. 2ib






4. A+bi






5. To simplify a complex fraction






6. We consider the a real number x to be the complex number x+ 0i and in this way we can think of the real numbers as a subset of






7. All the powers of i can be written as






8. A number that cannot be expressed as a fraction for any integer.






9. When two complex numbers are subtracted from one another.






10. Have radical






11. A subset within a field.






12. (a + bi)(c + bi) =






13. When you add two complex numbers a + bi and c + di - you get the sum of the real parts and the sum of the imaginary parts: (a + bi) + (c + di) = (a + c) + (b + d)i






14. z1z2* / |z2|²






15. Any set of elements that satisfies the field axioms for both addition and multiplication and is a commutative division algebra.






16. zn = (cos? + isin?)n = cosn? + isinn? - For all integers n

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17. Has exactly n roots by the fundamental theorem of algebra






18. 1






19. 1






20. When two complex numbers are divided.






21. (e^(-y) - e^(y)) / 2i = i sinh y






22. A² + b² - real and non negative






23. Not on the numberline






24. To prove that number field every algebraic equation in z with complex coefficients has a solution we need

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25. The field of numbers of the form - where and are real numbers and i is the imaginary unit equal to the square root of - . When a single letter is used to denote a complex number - it is sometimes called an 'affix.'






26. (2i+3)/(9-i)for the denominator you multiply by the conjugate and what u do to the bottom u have to do to the top then you distribute the bottom then the top then add like terms then you simplify. 21i+25/17






27. 1






28. Ln(r e^(i?)) = ln r + i(? + 2pn) - for all integers n






29. E^(ln r) e^(i?) e^(2pin)






30. Rotates anticlockwise by p/2






31. The complex number z representing a+bi.






32. Derives z = a+bi






33. ½(e^(iz) + e^(-iz))






34. Imaginary number

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35. When two complex numbers are added together.






36. E^(i?) = cos? + isin? ; e^(ip) + 1 = 0

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37. 1st. Rule of Complex Arithmetic






38. What about dividing one complex number by another? Is the result another complex number? Let's ask the question in another way. If you are given four real numbers a -b -c and d - can you find two other real numbers x and y so that






39. A complex number may be taken to the power of another complex number.






40. It is an amazing fact that by adjoining the imaginary unit i to the real numbers we obtain a complete number field called






41. 1. i^2 = -1 2. Every complex number has the 'Standard Form': a + bi for some real a and b. 3. For real a and b - a + bi = 0 if and only if a = b = 0 4. (a + bi) = (c + bi) = (a + c) + ( b + d)i 5. (a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc






42. The product of an imaginary number and its conjugate is






43. All numbers






44. The reals are just the






45. Has the opposite sign of a complex number; the conjugate of a + bi is a - bi






46. 3






47. In the same way that we think of real numbers as being points on a line - it is natural to identify a complex number z=a+ib with the point (a -b) in the cartesian plane.






48. V(zz*) = v(a² + b²)






49. x / r






50. R^2 = x