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CLEP General Mathematics: Complex Numbers

Subjects : clep, math
Instructions:
  • Answer 50 questions in 15 minutes.
  • If you are not ready to take this test, you can study here.
  • Match each statement with the correct term.
  • Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Formula: z1 · z2 = (a + bi)(c + di) = ac +adi +cbi +bdi² = (ac - bd) + (ad +cb)i - when you multiply a complex number by its conjugate - you get a real number.






2. E^(ln r) e^(i?) e^(2pin)






3. I^26/4= i^24 x i^2 =-1 so u divide the number by 4 and whatevers left over is the number that its equal to.






4. The reals are just the






5. Every complex number has the 'Standard Form':






6. When you subtract two complex numbers a + bi and c + di - you get the difference of the real parts and the difference of the imaginary parts: (a + bi) - (c + di) = (a - c) + (b - d)i






7. Any set of elements that satisfies the field axioms for both addition and multiplication and is a commutative division algebra.






8. All numbers






9. Where the curvature of the graph changes






10. Numbers on a numberline






11. ½(e^(-y) +e^(y)) = cosh y






12. The product of an imaginary number and its conjugate is






13. For real a and b - a + bi =






14. Cos n? + i sin n? (for all n integers)






15. 5th. Rule of Complex Arithmetic






16. 1






17. A plot of complex numbers as points.






18. When two complex numbers are divided.






19. x / r






20. 1






21. What about dividing one complex number by another? Is the result another complex number? Let's ask the question in another way. If you are given four real numbers a -b -c and d - can you find two other real numbers x and y so that






22. (2+i)(2i-3) you would use the foil methom which is first outter inner last. (2x2i)(2x-3)(ix2i^2)(ix(-3) =i-8






23. To simplify the square root of a negative number






24. (e^(iz) - e^(-iz)) / 2i






25. V(x² + y²) = |z|






26. Any number not rational






27. The complex number z representing a+bi.






28. y / r






29. A + bi






30. Derives z = a+bi






31. Written as fractions - terminating + repeating decimals






32. 3






33. To prove that number field every algebraic equation in z with complex coefficients has a solution we need

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34. 1. i^2 = -1 2. Every complex number has the 'Standard Form': a + bi for some real a and b. 3. For real a and b - a + bi = 0 if and only if a = b = 0 4. (a + bi) = (c + bi) = (a + c) + ( b + d)i 5. (a + bi)(c + bi) = ac + bci + adi + bdi^2 =(ac - bc






35. 2nd. Rule of Complex Arithmetic

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36. Divide moduli and subtract arguments






37. E ^ (z2 ln z1)






38. R?¹(cos? - isin?)






39. (a + bi) = (c + bi) =






40. In this amazing number field every algebraic equation in z with complex coefficients






41. The modulus of the complex number z= a + ib now can be interpreted as






42. If z= a+bi is a complex number and a and b are real - we say that a is the real part of z and that b is the imaginary part of z






43. No i






44. One of the numbers ... --2 --1 - 0 - 1 - 2 - ....






45. Rotates anticlockwise by p/2






46. The field of all rational and irrational numbers.






47. A + bi = z1 c + di = z2 - addition: z1 + z2 = (a + bi) + (c + di) = (a + c) + (b + d)i subtraction: z1 - z2 = (a - c) + (b - d)i






48. A subset within a field.






49. Like pi






50. 2ib