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GRE Math: Quantitative Formulas

Subjects : gre, math

Instructions:

Answer 45 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Convert 60% to a fraction
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
The sum of the digits is a multiple of 9.
3/5
A=pi*(r^2)

2. Volume of a rectangular box
X = Measure of interior angle/Circumference of circle 360
Sum of digits is a multiple of 3 and the last digit is even.
V=Lwh
A=l*w

3. Convert 33.33% to a fraction
SA= 2( Lw + Lh + w*h)
1/3
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
Add them. i.e. (5^7) * (5^3) = 5^10

4. Convert 75% to a fraction
3/4
The sum of the digits is a multiple of 9.
SA= 2( Lw + Lh + w*h)
M= (Y1-Y2)/(X1-X2)

5. Convert 80% to a fraction
4/5
2(pi(r^2))+ 2pirh
SA= 4pi(r^3)
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)

6. How to recognize a # as a multiple of 9
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
The sum of the digits is a multiple of 9.
4/5
P= 2L + 2w

7. When multiplying exponential #s with the same base - you do this to the exponents...
Add them. i.e. (5^7) * (5^3) = 5^10
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
V=(4/3)pi(r^3)
The sum of the digits is a multiple of 9.

8. Convert 83.33% to a fraction
A=pi*(r^2)
3/5
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
5/6

9. How to find the average of consecutive #s
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
V=Lwh
P= 2L + 2w

10. Surface area of a rectangular solid
1-sqrroot of 3-2
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
SA= 2( Lw + Lh + w*h)
The sum of the digits is a multiple of 9.

11. Convert 40% to a fraction
SA= 2( Lw + Lh + w*h)
The sum of the digits is a multiple of 9.
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
2/5

12. How to recognize if a # is a multiple of 12
4/5
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
2/3

13. Arc length
X = Measure of interior angle/Circumference of circle 360
SA= 4pi(r^3)
The sum of the digits is a multiple of 3
1/4

14. When solving an inequality - flip the sign when you....
The sum of the digits is a multiple of 3
1/4
Divide or multiply both sides by a NEGATIVE number
5/6

15. How to recognize a # as a multiple of 3
1-sqrroot of 3-2
The sum of the digits is a multiple of 3
Subtract them. i.e (5^7)/(5^3)= 5^4
SA= 4pi(r^3)

16. Area of a trapezoid
2/3
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
V=Lwh
A=l*w

17. Convert 66.66% to a fraction
X = Measure of interior angle/Circumference of circle 360
2/3
The sum of the digits is a multiple of 9.
1/8

18. Volume of a right circular cylinder
Pi(r^2)h
3/5
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
A=l*w

19. Surface area of a right circular cylinder
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
M= (Y1-Y2)/(X1-X2)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
2(pi(r^2))+ 2pirh

20. Convert 12.5% to a fraction
D=rt so r= d/t and t=d/r
5/6
X = Measure of interior angle/Area of Circle 360
1/8

21. Surface area of a sphere
3/5
SA= 2( Lw + Lh + w*h)
SA= 4pi(r^3)
Add them. i.e. (5^7) * (5^3) = 5^10

22. Area of a rectangle
Pi(r^2)h
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Subtract them. i.e (5^7)/(5^3)= 5^4
A=l*w

23. Area of a circle
3/4
A=pi*(r^2)
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
X = Measure of interior angle/Area of Circle 360

24. First 10 prime #s
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
2/3
Sum= (Average of Consecutive #s) * (# of terms in set)
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)

25. When asked to find the distance between 2 points on a graph use this formula...
4/5
P= 2L + 2w
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225

26. Circumference of a Circle
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
V=(4/3)pi(r^3)
C=2pir OR d*pi
2/3

27. Find hypotenuse of a right triangle given 2 side lengths
A=l*w
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
SA= 2( Lw + Lh + w*h)

28. Perfect Squares 1-15
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
A=l*w
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
V=(4/3)pi(r^3)

29. Area of a triangle
3/4
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
A= (1/2)b*h
2/5

30. Find distance when given time and rate
SA= 4pi(r^3)
Sum of digits is a multiple of 3 and the last digit is even.
D=rt so r= d/t and t=d/r
1/6

31. Convert 25% to a fraction
1/4
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
3/4
SA= 4pi(r^3)

32. Convert 16.66% to a fraction
Add them. i.e. (5^7) * (5^3) = 5^10
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
1/6
Sum= (Average of Consecutive #s) * (# of terms in set)

33. Volume of a sphere
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Divide or multiply both sides by a NEGATIVE number
Sum of digits is a multiple of 3 and the last digit is even.
V=(4/3)pi(r^3)

34. Quadratic Formula
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
M= (Y1-Y2)/(X1-X2)
3/4

35. Convert 20% to a fraction
1/5
C=2pir OR d*pi
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
Subtract them. i.e (5^7)/(5^3)= 5^4

36. When dividing exponential #s with the same base - you do this to the exponents...
A= (1/2)b*h
Subtract them. i.e (5^7)/(5^3)= 5^4
2(pi(r^2))+ 2pirh
A=pi*(r^2)

37. How to recognize a multiple of 6
Subtract them. i.e (5^7)/(5^3)= 5^4
1/4
Sum of digits is a multiple of 3 and the last digit is even.
Pi(r^2)h

38. Slope given 2 points
1-1-sqrroot of 2
Add them. i.e. (5^7) * (5^3) = 5^10
M= (Y1-Y2)/(X1-X2)
V=(4/3)pi(r^3)

39. Side lengths of a 30-60-90 right triangle
1/3
2/3
2(pi(r^2))+ 2pirh
1-sqrroot of 3-2

40. Perimeter of a rectangle
P= 2L + 2w
Add them. i.e. (5^7) * (5^3) = 5^10
1-sqrroot of 3-2
A=l*w

41. Area of parallelogram
M= (Y1-Y2)/(X1-X2)
5/6
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
A=b*h

42. How to recognize a # as a multiple of 4
The sum of the digits is a multiple of 9.
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)

43. How to find the sum of consecutive #s
Sum= (Average of Consecutive #s) * (# of terms in set)
SA= 2( Lw + Lh + w*h)
V=Lwh
Divide or multiply both sides by a NEGATIVE number

44. Area of a sector
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
X = Measure of interior angle/Area of Circle 360
2/3

45. Side lengths of a 45-45-90 right triangle
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
1-1-sqrroot of 2
5/6
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)