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GRE Math: Quantitative Formulas

Subjects : gre, math

Instructions:

Answer 45 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. When multiplying exponential #s with the same base - you do this to the exponents...
Add them. i.e. (5^7) * (5^3) = 5^10
SA= 4pi(r^3)
1/8
1/6

2. Circumference of a Circle
C=2pir OR d*pi
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
D=rt so r= d/t and t=d/r
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)

3. Convert 66.66% to a fraction
1-sqrroot of 3-2
3/4
2/3
X = Measure of interior angle/Circumference of circle 360

4. Quadratic Formula
1/4
1/6
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
SA= 4pi(r^3)

5. Area of a rectangle
2/5
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
A=l*w
5/6

6. Volume of a sphere
3/5
V=(4/3)pi(r^3)
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
Divide or multiply both sides by a NEGATIVE number

7. Convert 75% to a fraction
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
3/4
V=(4/3)pi(r^3)
A=b*h

8. Side lengths of a 30-60-90 right triangle
5/6
1-sqrroot of 3-2
Subtract them. i.e (5^7)/(5^3)= 5^4
D=rt so r= d/t and t=d/r

9. Arc length
X = Measure of interior angle/Circumference of circle 360
A= (1/2)b*h
X = Measure of interior angle/Area of Circle 360
Sum of digits is a multiple of 3 and the last digit is even.

10. Surface area of a sphere
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
1/8
SA= 4pi(r^3)
1/4

11. First 10 prime #s
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
D=rt so r= d/t and t=d/r
2/5
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29

12. Convert 83.33% to a fraction
5/6
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Subtract them. i.e (5^7)/(5^3)= 5^4

13. Convert 12.5% to a fraction
2/3
1/8
Divide or multiply both sides by a NEGATIVE number
1/5

14. How to recognize a # as a multiple of 9
5/6
A=b*h
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
The sum of the digits is a multiple of 9.

15. Volume of a right circular cylinder
Pi(r^2)h
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
V=Lwh

16. Convert 25% to a fraction
Divide or multiply both sides by a NEGATIVE number
4/5
A= (1/2)b*h
1/4

17. How to recognize a # as a multiple of 3
X = Measure of interior angle/Area of Circle 360
4/5
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
The sum of the digits is a multiple of 3

18. Convert 40% to a fraction
A=b*h
3/4
2/5
Sum of digits is a multiple of 3 and the last digit is even.

19. Area of a triangle
X = Measure of interior angle/Area of Circle 360
1/5
A= (1/2)b*h
1/8

20. Convert 60% to a fraction
3/5
A=l*w
1/8
A=pi*(r^2)

21. How to recognize a multiple of 6
4/5
V=Lwh
The sum of the digits is a multiple of 3
Sum of digits is a multiple of 3 and the last digit is even.

22. Convert 20% to a fraction
1/5
Subtract them. i.e (5^7)/(5^3)= 5^4
2(pi(r^2))+ 2pirh
Sum of digits is a multiple of 3 and the last digit is even.

23. Surface area of a right circular cylinder
2(pi(r^2))+ 2pirh
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
The sum of the digits is a multiple of 3
Add them. i.e. (5^7) * (5^3) = 5^10

24. Convert 33.33% to a fraction
1/3
V=Lwh
1/6
Pi(r^2)h

25. How to find the sum of consecutive #s
1-sqrroot of 3-2
Sum= (Average of Consecutive #s) * (# of terms in set)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
SA= 4pi(r^3)

26. When asked to find the distance between 2 points on a graph use this formula...
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
1/4
SA= 4pi(r^3)

27. Convert 80% to a fraction
4/5
X = Measure of interior angle/Circumference of circle 360
1/6
1/3

28. When solving an inequality - flip the sign when you....
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
3/4
Divide or multiply both sides by a NEGATIVE number
A= (1/2)b*h

29. Side lengths of a 45-45-90 right triangle
3/5
1-1-sqrroot of 2
The sum of the digits is a multiple of 3
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29

30. How to recognize a # as a multiple of 4
SA= 2( Lw + Lh + w*h)
A= (1/2)b*h
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.

31. Convert 16.66% to a fraction
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
1/6
1/4
1/8

32. Area of a trapezoid
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
P= 2L + 2w
Pi(r^2)h
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)

33. Find distance when given time and rate
D=rt so r= d/t and t=d/r
5/6
P= 2L + 2w
Sum= (Average of Consecutive #s) * (# of terms in set)

34. Perfect Squares 1-15
SA= 2( Lw + Lh + w*h)
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225

35. Area of a sector
X = Measure of interior angle/Area of Circle 360
P= 2L + 2w
1/6
1/8

36. Area of a circle
A=pi*(r^2)
1/4
A=l*w
1/3

37. How to find the average of consecutive #s
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
2/5
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)

38. Find hypotenuse of a right triangle given 2 side lengths
P= 2L + 2w
Pi(r^2)h
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
2(pi(r^2))+ 2pirh

39. Perimeter of a rectangle
Add them. i.e. (5^7) * (5^3) = 5^10
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
P= 2L + 2w
Subtract them. i.e (5^7)/(5^3)= 5^4

40. When dividing exponential #s with the same base - you do this to the exponents...
Subtract them. i.e (5^7)/(5^3)= 5^4
M= (Y1-Y2)/(X1-X2)
SA= 2( Lw + Lh + w*h)
Divide or multiply both sides by a NEGATIVE number

41. Area of parallelogram
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1-1-sqrroot of 2
A=b*h
X = Measure of interior angle/Circumference of circle 360

42. How to recognize if a # is a multiple of 12
Add them. i.e. (5^7) * (5^3) = 5^10
1/3
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
4/5

43. Volume of a rectangular box
1/3
2(pi(r^2))+ 2pirh
X = Measure of interior angle/Circumference of circle 360
V=Lwh

44. Slope given 2 points
2/5
M= (Y1-Y2)/(X1-X2)
1/8
1-sqrroot of 3-2

45. Surface area of a rectangular solid
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
C=2pir OR d*pi
SA= 2( Lw + Lh + w*h)
1-1-sqrroot of 2