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GRE Math: Quantitative Formulas

Subjects : gre, math

Instructions:

Answer 45 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Find hypotenuse of a right triangle given 2 side lengths
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
The sum of the digits is a multiple of 9.
A=l*w
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)

2. Convert 25% to a fraction
D=rt so r= d/t and t=d/r
X = Measure of interior angle/Circumference of circle 360
SA= 4pi(r^3)
1/4

3. Convert 80% to a fraction
The sum of the digits is a multiple of 9.
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
4/5
X = Measure of interior angle/Area of Circle 360

4. When multiplying exponential #s with the same base - you do this to the exponents...
X = Measure of interior angle/Circumference of circle 360
2/3
Add them. i.e. (5^7) * (5^3) = 5^10
P= 2L + 2w

5. Find distance when given time and rate
Sum of digits is a multiple of 3 and the last digit is even.
D=rt so r= d/t and t=d/r
Pi(r^2)h
4/5

6. Circumference of a Circle
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
Subtract them. i.e (5^7)/(5^3)= 5^4
C=2pir OR d*pi
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.

7. Convert 60% to a fraction
The sum of the digits is a multiple of 9.
3/5
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
D=rt so r= d/t and t=d/r

8. Arc length
X = Measure of interior angle/Circumference of circle 360
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
Sum= (Average of Consecutive #s) * (# of terms in set)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)

9. Side lengths of a 45-45-90 right triangle
1-1-sqrroot of 2
Sum= (Average of Consecutive #s) * (# of terms in set)
1/5
1-sqrroot of 3-2

10. Perfect Squares 1-15
3/4
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
The sum of the digits is a multiple of 3

11. Area of a sector
SA= 2( Lw + Lh + w*h)
M= (Y1-Y2)/(X1-X2)
4/5
X = Measure of interior angle/Area of Circle 360

12. Convert 33.33% to a fraction
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
3/5
X = Measure of interior angle/Circumference of circle 360
1/3

13. Convert 16.66% to a fraction
1/6
2/3
Sum= (Average of Consecutive #s) * (# of terms in set)
1-1-sqrroot of 2

14. Area of parallelogram
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
A=b*h
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]

15. Slope given 2 points
M= (Y1-Y2)/(X1-X2)
3/5
C=2pir OR d*pi
Pi(r^2)h

16. How to recognize if a # is a multiple of 12
D=rt so r= d/t and t=d/r
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
C=2pir OR d*pi

17. First 10 prime #s
2(pi(r^2))+ 2pirh
2/5
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
1/3

18. Surface area of a rectangular solid
V=Lwh
4/5
X = Measure of interior angle/Area of Circle 360
SA= 2( Lw + Lh + w*h)

19. Quadratic Formula
P= 2L + 2w
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
Add them. i.e. (5^7) * (5^3) = 5^10
5/6

20. How to recognize a # as a multiple of 4
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
A=l*w
Subtract them. i.e (5^7)/(5^3)= 5^4
V=(4/3)pi(r^3)

21. Convert 40% to a fraction
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
A=b*h
1-1-sqrroot of 2
2/5

22. Convert 83.33% to a fraction
A=pi*(r^2)
A=b*h
3/4
5/6

23. How to find the sum of consecutive #s
X = Measure of interior angle/Circumference of circle 360
Sum= (Average of Consecutive #s) * (# of terms in set)
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29

24. When asked to find the distance between 2 points on a graph use this formula...
A=b*h
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
Pi(r^2)h

25. Side lengths of a 30-60-90 right triangle
4/5
Divide or multiply both sides by a NEGATIVE number
X = Measure of interior angle/Circumference of circle 360
1-sqrroot of 3-2

26. How to recognize a # as a multiple of 3
1/4
The sum of the digits is a multiple of 3
5/6
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)

27. Convert 75% to a fraction
Add them. i.e. (5^7) * (5^3) = 5^10
1-1-sqrroot of 2
3/4
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]

28. Convert 20% to a fraction
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
M= (Y1-Y2)/(X1-X2)
1/5
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)

29. When dividing exponential #s with the same base - you do this to the exponents...
Subtract them. i.e (5^7)/(5^3)= 5^4
3/5
A=b*h
1/5

30. Volume of a sphere
V=(4/3)pi(r^3)
1/6
SA= 4pi(r^3)
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]

31. Convert 66.66% to a fraction
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
V=Lwh
Sum= (Average of Consecutive #s) * (# of terms in set)
2/3

32. Area of a rectangle
5/6
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
4/5
A=l*w

33. Area of a circle
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
The sum of the digits is a multiple of 9.
3/4
A=pi*(r^2)

34. Convert 12.5% to a fraction
Add them. i.e. (5^7) * (5^3) = 5^10
1/8
SA= 2( Lw + Lh + w*h)
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.

35. Perimeter of a rectangle
1/4
3/4
P= 2L + 2w
D=rt so r= d/t and t=d/r

36. How to recognize a multiple of 6
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
1-1-sqrroot of 2
P= 2L + 2w
Sum of digits is a multiple of 3 and the last digit is even.

37. How to find the average of consecutive #s
3/5
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
4/5
P= 2L + 2w

38. Area of a triangle
A= (1/2)b*h
2/5
3/4
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)

39. Volume of a rectangular box
V=Lwh
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
4/5

40. Volume of a right circular cylinder
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
1/3
Pi(r^2)h
1/6

41. How to recognize a # as a multiple of 9
2/5
P= 2L + 2w
The sum of the digits is a multiple of 3
The sum of the digits is a multiple of 9.

42. Area of a trapezoid
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
2/5
Divide or multiply both sides by a NEGATIVE number

43. When solving an inequality - flip the sign when you....
X = Measure of interior angle/Circumference of circle 360
Divide or multiply both sides by a NEGATIVE number
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
A=pi*(r^2)

44. Surface area of a right circular cylinder
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
2/3
Subtract them. i.e (5^7)/(5^3)= 5^4
2(pi(r^2))+ 2pirh

45. Surface area of a sphere
1/8
SA= 4pi(r^3)
M= (Y1-Y2)/(X1-X2)
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2