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GRE Math: Quantitative Formulas

Subjects : gre, math

Instructions:

Answer 45 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Convert 16.66% to a fraction
D=rt so r= d/t and t=d/r
1/6
SA= 4pi(r^3)
M= (Y1-Y2)/(X1-X2)

2. When asked to find the distance between 2 points on a graph use this formula...
X = Measure of interior angle/Area of Circle 360
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
1-1-sqrroot of 2

3. Side lengths of a 30-60-90 right triangle
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
1/4
1-sqrroot of 3-2
1/6

4. How to recognize a multiple of 6
Sum of digits is a multiple of 3 and the last digit is even.
Add them. i.e. (5^7) * (5^3) = 5^10
2/5
A=l*w

5. Surface area of a rectangular solid
1/8
X = Measure of interior angle/Circumference of circle 360
SA= 2( Lw + Lh + w*h)
SA= 4pi(r^3)

6. Area of parallelogram
3/5
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
A=b*h
A=l*w

7. Area of a trapezoid
3/5
Sum= (Average of Consecutive #s) * (# of terms in set)
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
The sum of the digits is a multiple of 9.

8. Find distance when given time and rate
1/5
D=rt so r= d/t and t=d/r
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
SA= 2( Lw + Lh + w*h)

9. How to recognize a # as a multiple of 4
A=l*w
Sum= (Average of Consecutive #s) * (# of terms in set)
P= 2L + 2w
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)

10. Convert 80% to a fraction
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
D=rt so r= d/t and t=d/r
1-sqrroot of 3-2
4/5

11. Slope given 2 points
M= (Y1-Y2)/(X1-X2)
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
A=b*h
X = Measure of interior angle/Circumference of circle 360

12. How to recognize if a # is a multiple of 12
Subtract them. i.e (5^7)/(5^3)= 5^4
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
Add them. i.e. (5^7) * (5^3) = 5^10
4/5

13. Convert 60% to a fraction
1/5
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
3/5
4/5

14. Volume of a rectangular box
V=Lwh
C=2pir OR d*pi
4/5
5/6

15. Convert 83.33% to a fraction
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
5/6
P= 2L + 2w
Divide or multiply both sides by a NEGATIVE number

16. Area of a rectangle
V=Lwh
A=l*w
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
Subtract them. i.e (5^7)/(5^3)= 5^4

17. Convert 33.33% to a fraction
3/4
A=l*w
Divide or multiply both sides by a NEGATIVE number
1/3

18. Convert 12.5% to a fraction
3/4
3/5
1/8
SA= 4pi(r^3)

19. Volume of a sphere
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
V=(4/3)pi(r^3)
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a

20. Circumference of a Circle
Add them. i.e. (5^7) * (5^3) = 5^10
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
C=2pir OR d*pi
2/3

21. Convert 25% to a fraction
V=(4/3)pi(r^3)
A= (1/2)b*h
A=b*h
1/4

22. Arc length
Sum of digits is a multiple of 3 and the last digit is even.
X = Measure of interior angle/Circumference of circle 360
The sum of the digits is a multiple of 3
1/4

23. When multiplying exponential #s with the same base - you do this to the exponents...
Divide or multiply both sides by a NEGATIVE number
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
Add them. i.e. (5^7) * (5^3) = 5^10
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225

24. Convert 66.66% to a fraction
Pi(r^2)h
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
3/5
2/3

25. When dividing exponential #s with the same base - you do this to the exponents...
Subtract them. i.e (5^7)/(5^3)= 5^4
Sum of digits is a multiple of 3 and the last digit is even.
X = Measure of interior angle/Circumference of circle 360
2/5

26. Convert 75% to a fraction
3/4
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
V=Lwh
Divide or multiply both sides by a NEGATIVE number

27. Quadratic Formula
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
SA= 2( Lw + Lh + w*h)
C=2pir OR d*pi
SA= 4pi(r^3)

28. How to find the sum of consecutive #s
1/8
Sum= (Average of Consecutive #s) * (# of terms in set)
V=(4/3)pi(r^3)
Subtract them. i.e (5^7)/(5^3)= 5^4

29. Surface area of a right circular cylinder
Sum of digits is a multiple of 3 and the last digit is even.
2(pi(r^2))+ 2pirh
1/3
SA= 4pi(r^3)

30. How to find the average of consecutive #s
A=l*w
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1/8
1/3

31. Perfect Squares 1-15
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1/5

32. Side lengths of a 45-45-90 right triangle
A=l*w
1-1-sqrroot of 2
V=(4/3)pi(r^3)
V=Lwh

33. Area of a triangle
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
1/5
A= (1/2)b*h
Subtract them. i.e (5^7)/(5^3)= 5^4

34. Perimeter of a rectangle
4/5
Divide or multiply both sides by a NEGATIVE number
P= 2L + 2w
Add them. i.e. (5^7) * (5^3) = 5^10

35. Surface area of a sphere
SA= 4pi(r^3)
A= (1/2)b*h
D=rt so r= d/t and t=d/r
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2

36. Area of a sector
3/5
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
1/3
X = Measure of interior angle/Area of Circle 360

37. Convert 40% to a fraction
1/5
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
2/5
The sum of the digits is a multiple of 9.

38. Area of a circle
Add them. i.e. (5^7) * (5^3) = 5^10
C=2pir OR d*pi
A=pi*(r^2)
Pi(r^2)h

39. Find hypotenuse of a right triangle given 2 side lengths
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
1/3
Sum of digits is a multiple of 3 and the last digit is even.
1/8

40. How to recognize a # as a multiple of 9
5/6
Pi(r^2)h
The sum of the digits is a multiple of 9.
A=b*h

41. Convert 20% to a fraction
Subtract them. i.e (5^7)/(5^3)= 5^4
2/5
1/5
V=Lwh

42. When solving an inequality - flip the sign when you....
3/4
Pi(r^2)h
Sum of digits is a multiple of 3 and the last digit is even.
Divide or multiply both sides by a NEGATIVE number

43. How to recognize a # as a multiple of 3
1/3
Sum of digits is a multiple of 3 and the last digit is even.
1/4
The sum of the digits is a multiple of 3

44. Volume of a right circular cylinder
3/4
SA= 4pi(r^3)
Pi(r^2)h
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)

45. First 10 prime #s
A=b*h
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
V=(4/3)pi(r^3)
The sum of the digits is a multiple of 3