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GRE Math: Quantitative Formulas

Subjects : gre, math

Instructions:

Answer 45 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Side lengths of a 30-60-90 right triangle
1-sqrroot of 3-2
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
Add them. i.e. (5^7) * (5^3) = 5^10
4/5

2. Convert 25% to a fraction
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
4/5
A= (1/2)b*h
1/4

3. Perfect Squares 1-15
Add them. i.e. (5^7) * (5^3) = 5^10
1-1-sqrroot of 2
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225

4. When multiplying exponential #s with the same base - you do this to the exponents...
Add them. i.e. (5^7) * (5^3) = 5^10
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
The sum of the digits is a multiple of 9.
M= (Y1-Y2)/(X1-X2)

5. Area of a triangle
Subtract them. i.e (5^7)/(5^3)= 5^4
2/5
1/5
A= (1/2)b*h

6. Convert 66.66% to a fraction
1-1-sqrroot of 2
2/5
2/3
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a

7. How to find the sum of consecutive #s
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
The sum of the digits is a multiple of 3
Divide or multiply both sides by a NEGATIVE number
Sum= (Average of Consecutive #s) * (# of terms in set)

8. Volume of a right circular cylinder
D=rt so r= d/t and t=d/r
4/5
Pi(r^2)h
The sum of the digits is a multiple of 9.

9. Side lengths of a 45-45-90 right triangle
1-1-sqrroot of 2
2(pi(r^2))+ 2pirh
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
3/5

10. When dividing exponential #s with the same base - you do this to the exponents...
A=b*h
Add them. i.e. (5^7) * (5^3) = 5^10
Subtract them. i.e (5^7)/(5^3)= 5^4
The sum of the digits is a multiple of 9.

11. Convert 60% to a fraction
1-sqrroot of 3-2
Add them. i.e. (5^7) * (5^3) = 5^10
3/5
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)

12. Quadratic Formula
D=rt so r= d/t and t=d/r
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
2(pi(r^2))+ 2pirh
V=Lwh

13. Surface area of a sphere
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
X = Measure of interior angle/Area of Circle 360
SA= 4pi(r^3)
1-1-sqrroot of 2

14. Convert 12.5% to a fraction
1/8
1/4
X = Measure of interior angle/Circumference of circle 360
D=rt so r= d/t and t=d/r

15. Area of a rectangle
V=Lwh
V=(4/3)pi(r^3)
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
A=l*w

16. Arc length
Subtract them. i.e (5^7)/(5^3)= 5^4
X = Measure of interior angle/Circumference of circle 360
Sum= (Average of Consecutive #s) * (# of terms in set)
5/6

17. Find hypotenuse of a right triangle given 2 side lengths
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
3/5
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
3/4

18. Convert 40% to a fraction
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
2/3
2/5
1/4

19. Area of a trapezoid
D=rt so r= d/t and t=d/r
1/4
3/4
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.

20. Perimeter of a rectangle
Add them. i.e. (5^7) * (5^3) = 5^10
5/6
Pi(r^2)h
P= 2L + 2w

21. Volume of a sphere
1/6
X = Measure of interior angle/Area of Circle 360
The sum of the digits is a multiple of 3
V=(4/3)pi(r^3)

22. Slope given 2 points
Divide or multiply both sides by a NEGATIVE number
A=b*h
A=pi*(r^2)
M= (Y1-Y2)/(X1-X2)

23. How to recognize a # as a multiple of 4
1-1-sqrroot of 2
Divide or multiply both sides by a NEGATIVE number
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
1-sqrroot of 3-2

24. How to recognize a # as a multiple of 3
5/6
The sum of the digits is a multiple of 3
1/5
Sum= (Average of Consecutive #s) * (# of terms in set)

25. Area of a circle
A=pi*(r^2)
3/5
1/6
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)

26. Area of a sector
A= (1/2)b*h
X = Measure of interior angle/Area of Circle 360
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
SA= 4pi(r^3)

27. Convert 16.66% to a fraction
1/6
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
P= 2L + 2w
2/3

28. Circumference of a Circle
3/4
C=2pir OR d*pi
3/5
V=(4/3)pi(r^3)

29. When asked to find the distance between 2 points on a graph use this formula...
A=b*h
M= (Y1-Y2)/(X1-X2)
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
The sum of the digits is a multiple of 3

30. How to recognize if a # is a multiple of 12
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
2(pi(r^2))+ 2pirh
SA= 2( Lw + Lh + w*h)
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]

31. How to find the average of consecutive #s
2/3
V=Lwh
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
M= (Y1-Y2)/(X1-X2)

32. Convert 80% to a fraction
4/5
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1-sqrroot of 3-2

33. First 10 prime #s
3/4
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
V=Lwh
The sum of the digits is a multiple of 9.

34. Convert 20% to a fraction
V=Lwh
1/5
Sum of digits is a multiple of 3 and the last digit is even.
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2

35. Area of parallelogram
A=b*h
SA= 4pi(r^3)
A=pi*(r^2)
Subtract them. i.e (5^7)/(5^3)= 5^4

36. How to recognize a multiple of 6
5/6
Sum of digits is a multiple of 3 and the last digit is even.
V=Lwh
1/3

37. When solving an inequality - flip the sign when you....
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
A=l*w
Divide or multiply both sides by a NEGATIVE number
V=(4/3)pi(r^3)

38. Convert 75% to a fraction
2(pi(r^2))+ 2pirh
V=(4/3)pi(r^3)
3/4
1/5

39. Find distance when given time and rate
A= (1/2)b*h
D=rt so r= d/t and t=d/r
Sum of digits is a multiple of 3 and the last digit is even.
A=pi*(r^2)

40. Surface area of a right circular cylinder
SA= 2( Lw + Lh + w*h)
4/5
5/6
2(pi(r^2))+ 2pirh

41. Convert 33.33% to a fraction
1/3
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
M= (Y1-Y2)/(X1-X2)
P= 2L + 2w

42. How to recognize a # as a multiple of 9
A=b*h
1/5
The sum of the digits is a multiple of 9.
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.

43. Volume of a rectangular box
Subtract them. i.e (5^7)/(5^3)= 5^4
V=Lwh
1/6
P= 2L + 2w

44. Convert 83.33% to a fraction
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
5/6
3/4
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a

45. Surface area of a rectangular solid
SA= 2( Lw + Lh + w*h)
1/5
The sum of the digits is a multiple of 3
2/5