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Test your basic knowledge |
GRE Math: Quantitative Formulas
Start Test
Study First
Subjects
:
gre
,
math
Instructions:
Answer 45 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. How to find the average of consecutive #s
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
2/5
Add them. i.e. (5^7) * (5^3) = 5^10
A=l*w
2. Area of a triangle
1/5
Divide or multiply both sides by a NEGATIVE number
A= (1/2)b*h
4/5
3. Convert 40% to a fraction
2/5
D=rt so r= d/t and t=d/r
V=Lwh
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
4. Find hypotenuse of a right triangle given 2 side lengths
2/3
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
5. Area of a sector
X = Measure of interior angle/Area of Circle 360
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
V=Lwh
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
6. Area of a circle
1/4
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
A=pi*(r^2)
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
7. Convert 16.66% to a fraction
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
The sum of the digits is a multiple of 9.
1/6
Add them. i.e. (5^7) * (5^3) = 5^10
8. Surface area of a sphere
Subtract them. i.e (5^7)/(5^3)= 5^4
V=Lwh
A=l*w
SA= 4pi(r^3)
9. Side lengths of a 30-60-90 right triangle
3/4
1-sqrroot of 3-2
1-1-sqrroot of 2
3/5
10. When asked to find the distance between 2 points on a graph use this formula...
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
Add them. i.e. (5^7) * (5^3) = 5^10
2(pi(r^2))+ 2pirh
A=pi*(r^2)
11. Quadratic Formula
1/3
M= (Y1-Y2)/(X1-X2)
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
V=Lwh
12. How to recognize a multiple of 6
X = Measure of interior angle/Circumference of circle 360
Sum of digits is a multiple of 3 and the last digit is even.
A=pi*(r^2)
3/5
13. Convert 83.33% to a fraction
P= 2L + 2w
3/4
4/5
5/6
14. Volume of a right circular cylinder
Pi(r^2)h
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1/3
P= 2L + 2w
15. First 10 prime #s
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Subtract them. i.e (5^7)/(5^3)= 5^4
SA= 2( Lw + Lh + w*h)
16. Find distance when given time and rate
1-sqrroot of 3-2
1/4
D=rt so r= d/t and t=d/r
5/6
17. Perimeter of a rectangle
Sum= (Average of Consecutive #s) * (# of terms in set)
P= 2L + 2w
A= (1/2)b*h
Divide or multiply both sides by a NEGATIVE number
18. Slope given 2 points
M= (Y1-Y2)/(X1-X2)
1/6
3/5
5/6
19. Convert 25% to a fraction
The sum of the digits is a multiple of 9.
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
1/4
M= (Y1-Y2)/(X1-X2)
20. Convert 33.33% to a fraction
Add them. i.e. (5^7) * (5^3) = 5^10
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
1/3
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
21. Area of a rectangle
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
A=l*w
SA= 2( Lw + Lh + w*h)
1/6
22. When dividing exponential #s with the same base - you do this to the exponents...
Subtract them. i.e (5^7)/(5^3)= 5^4
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
3/4
Divide or multiply both sides by a NEGATIVE number
23. Side lengths of a 45-45-90 right triangle
1-1-sqrroot of 2
Sum= (Average of Consecutive #s) * (# of terms in set)
1/3
5/6
24. Arc length
X = Measure of interior angle/Circumference of circle 360
3/5
D=rt so r= d/t and t=d/r
1/8
25. How to recognize a # as a multiple of 9
5/6
Divide or multiply both sides by a NEGATIVE number
The sum of the digits is a multiple of 9.
P= 2L + 2w
26. Convert 75% to a fraction
D=rt so r= d/t and t=d/r
V=Lwh
M= (Y1-Y2)/(X1-X2)
3/4
27. Circumference of a Circle
1/8
C=2pir OR d*pi
X = Measure of interior angle/Circumference of circle 360
3/5
28. Convert 20% to a fraction
X = Measure of interior angle/Area of Circle 360
1/5
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
The sum of the digits is a multiple of 3
29. Area of a trapezoid
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
3/4
SA= 4pi(r^3)
C=2pir OR d*pi
30. Surface area of a right circular cylinder
2(pi(r^2))+ 2pirh
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
4/5
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
31. Perfect Squares 1-15
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
Take the average of the largest and smallest # in the set. (i.e. for the set of consecutive #s 5....172 would be (172+5)/(2)= 88.5)
The sum of the digits is a multiple of 3
1 - 4 - 9 - 16 - 25 - 36 - 49 - 64 - 81 - 100 - 121 - 144 - 169 - 196 - 225
32. Volume of a rectangular box
4/5
SA= 2( Lw + Lh + w*h)
V=Lwh
A=b*h
33. Convert 60% to a fraction
1-sqrroot of 3-2
D=rt so r= d/t and t=d/r
3/5
A= (1/2)b*h
34. Convert 66.66% to a fraction
2/3
A=l*w
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
V=(4/3)pi(r^3)
35. How to recognize if a # is a multiple of 12
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
A=l*w
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
1/3
36. When multiplying exponential #s with the same base - you do this to the exponents...
A=pi*(r^2)
3/4
Add them. i.e. (5^7) * (5^3) = 5^10
1/8
37. When solving an inequality - flip the sign when you....
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
Add them. i.e. (5^7) * (5^3) = 5^10
Divide or multiply both sides by a NEGATIVE number
SA= 4pi(r^3)
38. How to find the sum of consecutive #s
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
2/5
Sum= (Average of Consecutive #s) * (# of terms in set)
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
39. How to recognize a # as a multiple of 4
M= (Y1-Y2)/(X1-X2)
The last 2 digits are a multiple of 4. (i.e 144. 44 is a multiple of 4 - so 144 must also be a multiple of 4.)
1/3
The sum of the digits it a multiple of 3 and the last two digits is a multiple of 4. (i.e 144: 1+4+4=9 which is a multiple of 3 - and 44 is a multiple of 4 - so 144 is a multiple of 12.)
40. Volume of a sphere
V=(4/3)pi(r^3)
Distance formula. Distance= Sqrareroot[((Xa-Xb)^2) + ((Ya-Yb)^2)]
Pythagorean Theorem: h^2= (S1)^2 + (S2)^2
Subtract them. i.e (5^7)/(5^3)= 5^4
41. Convert 80% to a fraction
The sum of the digits is a multiple of 3
2/5
4/5
1/4
42. Area of parallelogram
A= (1/2)h*(a+b) where a is the length of the bottom base and b is the length of the top base.
Divide or multiply both sides by a NEGATIVE number
A=b*h
Sum= (Average of Consecutive #s) * (# of terms in set)
43. How to recognize a # as a multiple of 3
A=b*h
1-sqrroot of 3-2
The sum of the digits is a multiple of 3
2 - 3 - 5 - 7 - 11 - 13 - 17 - 19 - 23 - 29
44. Convert 12.5% to a fraction
Add them. i.e. (5^7) * (5^3) = 5^10
X= -b (+/-) Sqrroot [(b^2) -4ac)]/2a
X = Measure of interior angle/Circumference of circle 360
1/8
45. Surface area of a rectangular solid
1/3
1/4
SA= 2( Lw + Lh + w*h)
Sum of digits is a multiple of 3 and the last digit is even.