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SAT Math Subject Test 1 And 2

Subjects : sat, math

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Face diagonal of a cube
The angle is a right angle
V = (1/3)bh (where b is the area of the base figure)
F = sroot2
((amount change) / (original)) x 100

2. Relation between central angle and minor arc
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Right angle formed from height radius and slant
Long diagonal of solid is equal to diameter of sphere
(degree/360) x pir^2

3. 4 Properties of a parallelogram
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
A = 1/2absinx (where x is included angle of sides a and b)
Circumscribed
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea

4. Percent change
Both solids have same diameter
D = sroot3
((amount change) / (original)) x 100
SA = pirl + pir^2 (where l is slant of cone)

5. What do you use to solve for direct variation?
Proportion (ratio is same)
F = sroot2
Sphere (same radii)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

6. Surface area of a pyramid
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
D = sroot3
Sum of the area of each face (no definite equation)
A = 1/2absinx (where x is included angle of sides a and b)

7. Long diagonal of a cylinder
A = absinx (where x is the angle between sides a and b)
A= pir^2
D^2 = 4r^2 + h^2 (pythagorean theorem)
Cone

8. Three properties of tangent lines extending from a point to a circle

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9. (x+y)(x-y)
x^2 - y^2
SA = pirl + pir^2 (where l is slant of cone)
V = (1/3)bh (where b is the area of the base figure)
Cone

10. In an inequality - what conjunction is used with greater than
Or
Distance / rate
A = bh (both sides of the rectangle)
SA = 2pir^2 + 2pirh

11. Volume of a cube
D = sroot3
(4/3)pir^3
V = (1/3)pir^2h
Inscribed

12. a shape that is in another shape - placed inside that shape with tightest fit possible
And
x^2 - 2xy + y^2
Inscribed
SA = 6s^2

13. Area of a sector
A = h/2 (b1 + b2)
(degree/360) x pir^2
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Original x (1 - rate)^number of changes

14. Volume of a pyramid
A = bh (h is hight from base to vertex and creating a right angle)
Or
SA = 2lw + 2hw + 2lh
V = (1/3)bh (where b is the area of the base figure)

15. Volume of a sphere
Both solids have same diameter
V = s^3
V= pir^2h
(4/3)pir^3

16. Circle rotated around its diameter
Total = number of things x average
Sphere (same radii)
Or
A = bh (both sides of the rectangle)

17. Area of a triangle (trig)
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
A = 1/2absinx (where x is included angle of sides a and b)
Inscribed
Both solids have same diameter

18. Area of a parallelogram (geometry)
Right angle formed from height radius and slant
((amount change) / (original)) x 100
A = bh (h is hight from base to vertex and creating a right angle)
V= pir^2h

19. In an inequality - what conjunction is used with less than
1. two equal sides 2. two equal angles of those sides
And
A = 1/2bh
Prime number (2 is only even prime number - 1 and 0 are not prime)

20. Isosceles triangle rotated around axis of symmetry
x^2 - y^2
Cone
Prime number (2 is only even prime number - 1 and 0 are not prime)
Distance / rate

21. Area of a trapezoid
A = 1/2bh
V = s^3
V= pir^2h
A = h/2 (b1 + b2)

22. Area of a parallelogram (trig)
Inscribed angle will be half of arc (and therefore half of central angle)
A = absinx (where x is the angle between sides a and b)
Both solids have same diameter
Sum of the area of each face (no definite equation)

23. Long diagonal of a rectangular solid
SA = pirl + pir^2 (where l is slant of cone)
SA 4pir^2
Prime number (2 is only even prime number - 1 and 0 are not prime)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

24. Surface area of a sphere
SA 4pir^2
The angle is a right angle
A = bh (both sides of the rectangle)
V = s^3

25. Average pie
Total = number of things x average
(degree/360) x 2pir
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
D^2 = 4r^2 + h^2 (pythagorean theorem)

26. Relation between inscribed angle and minor arc
And
Long diagonal of solid is equal to diameter of sphere
Inscribed angle will be half of arc (and therefore half of central angle)
SA = 2lw + 2hw + 2lh

27. Surface area of a cylinder
SA = 2pir^2 + 2pirh
Sphere (same radii)
Circumscribed
SA = 6s^2

28. One property any angle inscribed in a semi-cricle has
1. two equal sides 2. two equal angles of those sides
F = sroot2
The angle is a right angle
V = lwh

29. Volume of a rectangular solid
Both will be same fraction of circle (60 degrees = 1/6 of circle)
V = lwh
Cylinder
SA = 2lw + 2hw + 2lh

30. Percent increase
Remainder (note all remainders are always integers)
Original x (1 + rate)^number of changes
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
A = bh (both sides of the rectangle)

31. length of an arc
(degree/360) x 2pir
V = lwh
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
Right angle formed from height radius and slant

32. The integer left over after dividing two numbers
V = (1/3)pir^2h
Remainder (note all remainders are always integers)
A = absinx (where x is the angle between sides a and b)
D^2 = 4r^2 + h^2 (pythagorean theorem)

33. Volume of a cube
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
V= pir^2h
V = s^3
Long diagonal of solid is equal to diameter of sphere

34. Area of a rectangle
SA = pirl + pir^2 (where l is slant of cone)
A = bh (both sides of the rectangle)
Original x (1 + rate)^number of changes
1. two equal sides 2. two equal angles of those sides

35. Right triangle rotated around one leg
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Cone
Or
A= pir^2

36. Time =
SA = 2lw + 2hw + 2lh
Cone
Distance / rate
SA 4pir^2

37. Percent decrease
Original x (1 - rate)^number of changes
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Proportion (ratio is same)

38. Surface area of a cone
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
SA = pirl + pir^2 (where l is slant of cone)
Total = number of things x average
Proportion (ratio is same)

39. Cube or rectangular solid inscribed in a sphere
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
V = (1/3)pir^2h
Long diagonal of solid is equal to diameter of sphere
D = sroot3

40. Main property of a cone
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
Remainder (note all remainders are always integers)
Right angle formed from height radius and slant
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

41. a shape drawn around another shape with the tighets fit possible
A = absinx (where x is the angle between sides a and b)
Long diagonal of solid is equal to diameter of sphere
Inscribed angle will be half of arc (and therefore half of central angle)
Circumscribed

42. (x+y)^2
Original x (1 - rate)^number of changes
A= pir^2
x^2 + 2xy + y^2
Both solids have same diameter

43. What two triangles compose a square?
Circumscribed
SA = 2pir^2 + 2pirh
SA = pirl + pir^2 (where l is slant of cone)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2

44. 2 additional properties of a rectangle
1. all sides are same length 2. all angles are same size
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
SA = pirl + pir^2 (where l is slant of cone)
(degree/360) x 2pir

45. Volume of a cylinder
(4/3)pir^3
V= pir^2h
Distance / rate
SA = pirl + pir^2 (where l is slant of cone)

46. Circumference of a circle
x^2 + 2xy + y^2
C = 2pir (or C = pi x d)
Cone
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency

47. Long diagonal of a cube
D = sroot3
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
The angle is a right angle
x^2 - 2xy + y^2

48. Surface area of a cube
D = sroot3
Circumscribed
SA = 6s^2
V = s^3

49. What do you use to solve for indirect variation?
A = h/2 (b1 + b2)
Multiplication (product is same)
x^2 + 2xy + y^2
D^2 = 4r^2 + h^2 (pythagorean theorem)

50. Surface area of a rectangular solid
V = (1/3)pir^2h
SA = 2lw + 2hw + 2lh
D^2 = 4r^2 + h^2 (pythagorean theorem)
(degree/360) x pir^2