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SAT Math Subject Test 1 And 2

Subjects : sat, math

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. What do you use to solve for indirect variation?
Prime number (2 is only even prime number - 1 and 0 are not prime)
Multiplication (product is same)
Original x (1 - rate)^number of changes
Circumscribed

2. In an inequality - what conjunction is used with less than
And
Both will be same fraction of circle (60 degrees = 1/6 of circle)
(degree/360) x pir^2
Cylinder

3. Volume of a rectangular solid
SA 4pir^2
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
V = lwh
((amount change) / (original)) x 100

4. What do you use to solve for direct variation?
V = s^3
Proportion (ratio is same)
Both solids have same diameter
A= pir^2

5. Area of a sector
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
(degree/360) x pir^2
And
SA 4pir^2

6. Circle rotated around its diameter
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
Sphere (same radii)
V = (1/3)pir^2h
D = sroot3

7. Main property of a cone
Remainder (note all remainders are always integers)
x^2 - y^2
1. two equal sides 2. two equal angles of those sides
Right angle formed from height radius and slant

8. What two triangles compose a square?
Long diagonal of solid is equal to diameter of sphere
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Cone
V = s^3

9. Area of a triangle (geometry)
V= pir^2h
A = 1/2bh
SA = pirl + pir^2 (where l is slant of cone)
A = bh (h is hight from base to vertex and creating a right angle)

10. Volume of a cylinder
V= pir^2h
1. two equal sides 2. two equal angles of those sides
Cone
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

11. (x-y)^2
Circumscribed
SA = 2pir^2 + 2pirh
x^2 - 2xy + y^2
SA = 6s^2

12. Surface area of a cylinder
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Cylinder
SA = 2pir^2 + 2pirh
A = bh (both sides of the rectangle)

13. An integer that has exactly two distinct factors: itself and 1
Prime number (2 is only even prime number - 1 and 0 are not prime)
Right angle formed from height radius and slant
Total = number of things x average
SA 4pir^2

14. Sum of Angle formula (regular polygons)
And
(n-2)180 (divide this by n to find individual angle measures)
D = sroot3
Original x (1 - rate)^number of changes

15. Relation between inscribed angle and minor arc
(degree/360) x pir^2
A = absinx (where x is the angle between sides a and b)
Prime number (2 is only even prime number - 1 and 0 are not prime)
Inscribed angle will be half of arc (and therefore half of central angle)

16. The integer left over after dividing two numbers
D = sroot3
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Remainder (note all remainders are always integers)
Proportion (ratio is same)

17. One property any angle inscribed in a semi-cricle has
F = sroot2
The angle is a right angle
C = 2pir (or C = pi x d)
(4/3)pir^3

18. Area of a circle
A= pir^2
Inscribed angle will be half of arc (and therefore half of central angle)
SA 4pir^2
Both will be same fraction of circle (60 degrees = 1/6 of circle)

19. Average pie
V = lwh
SA = 6s^2
Total = number of things x average
A = bh (both sides of the rectangle)

20. 2 additional properties of a rectangle
A= pir^2
V = s^3
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
Both solids have same diameter

21. Sphere inscribed in a cylinder
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Both solids have same diameter
V= pir^2h
The angle is a right angle

22. Cube or rectangular solid inscribed in a sphere
SA = 2lw + 2hw + 2lh
D^2 = 4r^2 + h^2 (pythagorean theorem)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Long diagonal of solid is equal to diameter of sphere

23. Volume of a sphere
A = bh (h is hight from base to vertex and creating a right angle)
Total = number of things x average
(4/3)pir^3
((amount change) / (original)) x 100

24. (x+y)^2
x^2 + 2xy + y^2
Long diagonal of solid is equal to diameter of sphere
V= pir^2h
V = (1/3)pir^2h

25. Three properties of tangent lines extending from a point to a circle

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26. Rectangle rotated around a central line or one side
V= pir^2h
Cylinder
x^2 - 2xy + y^2
x^2 - y^2

27. Circumference of a circle
Cone
C = 2pir (or C = pi x d)
The angle is a right angle
Original x (1 + rate)^number of changes

28. In an inequality - what conjunction is used with greater than
Both solids have same diameter
(degree/360) x pir^2
D = sroot3
Or

29. Face diagonal of a cube
Prime number (2 is only even prime number - 1 and 0 are not prime)
F = sroot2
A = bh (h is hight from base to vertex and creating a right angle)
D^2 = 4r^2 + h^2 (pythagorean theorem)

30. What 2 properties does an isosceles triangle have?
V = (1/3)bh (where b is the area of the base figure)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
1. two equal sides 2. two equal angles of those sides
F = sroot2

31. Long diagonal of a cylinder
D^2 = 4r^2 + h^2 (pythagorean theorem)
Both solids have same diameter
1. all sides are same length 2. all angles are same size
C = 2pir (or C = pi x d)

32. Percent change
((amount change) / (original)) x 100
C = 2pir (or C = pi x d)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
F = sroot2

33. Long diagonal of a cube
D = sroot3
Sphere (same radii)
Cone
Circumscribed

34. length of an arc
Sphere (same radii)
(degree/360) x 2pir
SA 4pir^2
Inscribed angle will be half of arc (and therefore half of central angle)

35. Relation between central angle and minor arc
Both will be same fraction of circle (60 degrees = 1/6 of circle)
A = 1/2bh
V = (1/3)bh (where b is the area of the base figure)
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)

36. Surface area of a sphere
F = sroot2
A = 1/2absinx (where x is included angle of sides a and b)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
SA 4pir^2

37. Surface area of a pyramid
D = sroot3
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Sum of the area of each face (no definite equation)
A = 1/2absinx (where x is included angle of sides a and b)

38. 2 properties of regular polygon
Multiplication (product is same)
Prime number (2 is only even prime number - 1 and 0 are not prime)
A = bh (both sides of the rectangle)
1. all sides are same length 2. all angles are same size

39. Surface area of a rectangular solid
((amount change) / (original)) x 100
And
SA = 2lw + 2hw + 2lh
Inscribed angle will be half of arc (and therefore half of central angle)

40. Two equations for Area of a square
Distance / rate
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Prime number (2 is only even prime number - 1 and 0 are not prime)
And

41. Surface area of a cube
x^2 - 2xy + y^2
Both will be same fraction of circle (60 degrees = 1/6 of circle)
SA = 6s^2
A= pir^2

42. (x+y)(x-y)
Cone
x^2 - y^2
Or
(degree/360) x 2pir

43. Surface area of a cone
Diameter of sphere is equal to length of cube's side
SA = 6s^2
SA = pirl + pir^2 (where l is slant of cone)
A = 1/2absinx (where x is included angle of sides a and b)

44. Percent decrease
D = sroot3
Multiplication (product is same)
(degree/360) x 2pir
Original x (1 - rate)^number of changes

45. Area of a parallelogram (trig)
A = absinx (where x is the angle between sides a and b)
Cone
V = s^3
Or

46. Area of a trapezoid
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
A= pir^2
D^2 = 4r^2 + h^2 (pythagorean theorem)
A = h/2 (b1 + b2)

47. Right triangle rotated around one leg
SA = 6s^2
A = bh (both sides of the rectangle)
Or
Cone

48. Sphere inscribed in a cube

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49. Percent increase
Original x (1 + rate)^number of changes
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Both solids have same diameter
A = absinx (where x is the angle between sides a and b)

50. Volume of a pyramid
V = (1/3)bh (where b is the area of the base figure)
Proportion (ratio is same)
Long diagonal of solid is equal to diameter of sphere
A = bh (h is hight from base to vertex and creating a right angle)