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SAT Math Subject Test 1 And 2

Subjects : sat, math

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Area of a trapezoid
A = h/2 (b1 + b2)
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
A= pir^2
A = absinx (where x is the angle between sides a and b)

2. Surface area of a cylinder
SA = 2pir^2 + 2pirh
V = lwh
Proportion (ratio is same)
V= pir^2h

3. Area of a parallelogram (geometry)
Right angle formed from height radius and slant
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
A = bh (h is hight from base to vertex and creating a right angle)
Inscribed angle will be half of arc (and therefore half of central angle)

4. In an inequality - what conjunction is used with greater than
C = 2pir (or C = pi x d)
Or
A = h/2 (b1 + b2)
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency

5. Cylinder inscribed in a sphere

6. Volume of a cube
V = s^3
x^2 - y^2
C = 2pir (or C = pi x d)
Proportion (ratio is same)

7. Volume of a pyramid
SA = pirl + pir^2 (where l is slant of cone)
V = s^3
V = (1/3)bh (where b is the area of the base figure)
Cylinder

8. Surface area of a pyramid
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
Sum of the area of each face (no definite equation)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Inscribed

9. Rectangle rotated around a central line or one side
V = (1/3)bh (where b is the area of the base figure)
Cylinder
Right angle formed from height radius and slant
x^2 - y^2

10. An integer that has exactly two distinct factors: itself and 1
Diameter of sphere is equal to length of cube's side
Total = number of things x average
Inscribed
Prime number (2 is only even prime number - 1 and 0 are not prime)

11. Area of a triangle (trig)
Cone
A = 1/2absinx (where x is included angle of sides a and b)
SA = 6s^2
SA = 2pir^2 + 2pirh

12. Circle rotated around its diameter
Sphere (same radii)
((amount change) / (original)) x 100
(degree/360) x 2pir
SA = 2lw + 2hw + 2lh

13. length of an arc
x^2 - y^2
A = bh (both sides of the rectangle)
Remainder (note all remainders are always integers)
(degree/360) x 2pir

14. In an inequality - what conjunction is used with less than
Multiplication (product is same)
And
Sum of the area of each face (no definite equation)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

15. Cube or rectangular solid inscribed in a sphere
Long diagonal of solid is equal to diameter of sphere
The angle is a right angle
SA = 2lw + 2hw + 2lh
(degree/360) x 2pir

16. Long diagonal of a cube
x^2 + 2xy + y^2
A = absinx (where x is the angle between sides a and b)
D = sroot3
A = h/2 (b1 + b2)

17. Percent increase
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
A = 1/2absinx (where x is included angle of sides a and b)
Original x (1 + rate)^number of changes
Diameter of sphere is equal to length of cube's side

18. Area of a circle
Or
C = 2pir (or C = pi x d)
x^2 - 2xy + y^2
A= pir^2

19. Percent change
((amount change) / (original)) x 100
V = (1/3)pir^2h
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
D^2 = 4r^2 + h^2 (pythagorean theorem)

20. Surface area of a cone
SA = pirl + pir^2 (where l is slant of cone)
D = sroot3
SA = 2pir^2 + 2pirh
And

21. Sphere inscribed in a cylinder
V= pir^2h
Diameter of sphere is equal to length of cube's side
Both solids have same diameter
A = absinx (where x is the angle between sides a and b)

22. 4 Properties of a parallelogram
SA = 2lw + 2hw + 2lh
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
SA 4pir^2
SA = 6s^2

23. Two equations for Area of a square
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Cone
Inscribed angle will be half of arc (and therefore half of central angle)
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length

24. Face diagonal of a cube
A= pir^2
Cylinder
F = sroot2
D^2 = 4r^2 + h^2 (pythagorean theorem)

25. Circumference of a circle
A= pir^2
V = (1/3)pir^2h
Distance / rate
C = 2pir (or C = pi x d)

26. Volume of a cylinder
1. all sides are same length 2. all angles are same size
V= pir^2h
SA = 2lw + 2hw + 2lh
Sphere (same radii)

27. What do you use to solve for indirect variation?
Multiplication (product is same)
SA = 2lw + 2hw + 2lh
Original x (1 - rate)^number of changes
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea

28. Time =
Distance / rate
Cone
x^2 - y^2
SA = 2pir^2 + 2pirh

29. Isosceles triangle rotated around axis of symmetry
Prime number (2 is only even prime number - 1 and 0 are not prime)
A = absinx (where x is the angle between sides a and b)
V= pir^2h
Cone

30. a shape that is in another shape - placed inside that shape with tightest fit possible
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Inscribed
V = (1/3)bh (where b is the area of the base figure)
1. all sides are same length 2. all angles are same size

31. Area of a sector
(4/3)pir^3
(degree/360) x pir^2
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
A = 1/2bh

32. Sphere inscribed in a cube

33. Volume of a rectangular solid
V = s^3
D^2 = 4r^2 + h^2 (pythagorean theorem)
x^2 + 2xy + y^2
V = lwh

34. Surface area of a cube
A = h/2 (b1 + b2)
V = (1/3)bh (where b is the area of the base figure)
V = s^3
SA = 6s^2

35. What do you use to solve for direct variation?
F = sroot2
A = 1/2absinx (where x is included angle of sides a and b)
x^2 + 2xy + y^2
Proportion (ratio is same)

36. Percent decrease
(degree/360) x pir^2
A = absinx (where x is the angle between sides a and b)
Original x (1 - rate)^number of changes
Prime number (2 is only even prime number - 1 and 0 are not prime)

37. What two triangles compose a square?
A = 1/2absinx (where x is included angle of sides a and b)
A = absinx (where x is the angle between sides a and b)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
F = sroot2

38. Area of a parallelogram (trig)
A = absinx (where x is the angle between sides a and b)
A = bh (both sides of the rectangle)
1. all sides are same length 2. all angles are same size
x^2 - y^2

39. One property any angle inscribed in a semi-cricle has
The angle is a right angle
SA 4pir^2
D^2 = 4r^2 + h^2 (pythagorean theorem)
Prime number (2 is only even prime number - 1 and 0 are not prime)

40. What 2 properties does an isosceles triangle have?
1. two equal sides 2. two equal angles of those sides
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Proportion (ratio is same)

41. Volume of a cube
V = (1/3)pir^2h
SA = 6s^2
(n-2)180 (divide this by n to find individual angle measures)
Cylinder

42. Average pie
Sum of the area of each face (no definite equation)
A = bh (h is hight from base to vertex and creating a right angle)
Total = number of things x average
Inscribed angle will be half of arc (and therefore half of central angle)

43. (x+y)(x-y)
V = (1/3)pir^2h
Inscribed
(degree/360) x pir^2
x^2 - y^2

44. The integer left over after dividing two numbers
A = 1/2bh
Remainder (note all remainders are always integers)
A = absinx (where x is the angle between sides a and b)
((amount change) / (original)) x 100

45. Surface area of a sphere
Sphere (same radii)
V = (1/3)bh (where b is the area of the base figure)
Inscribed angle will be half of arc (and therefore half of central angle)
SA 4pir^2

46. (x+y)^2
Remainder (note all remainders are always integers)
Or
x^2 + 2xy + y^2
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

47. a shape drawn around another shape with the tighets fit possible
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
Circumscribed
A= pir^2
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

48. (x-y)^2
x^2 - 2xy + y^2
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Both solids have same diameter
SA = pirl + pir^2 (where l is slant of cone)

49. 2 properties of regular polygon
1. all sides are same length 2. all angles are same size
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Both will be same fraction of circle (60 degrees = 1/6 of circle)
x^2 - 2xy + y^2

50. Area of a triangle (geometry)
D = sroot3
A = 1/2bh
Proportion (ratio is same)
(4/3)pir^3