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SAT Math Subject Test 1 And 2

Subjects : sat, math

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Face diagonal of a cube
Sum of the area of each face (no definite equation)
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
A = h/2 (b1 + b2)
F = sroot2

2. Volume of a cube
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Right angle formed from height radius and slant
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
V = s^3

3. What do you use to solve for direct variation?
SA = 2pir^2 + 2pirh
Original x (1 - rate)^number of changes
(degree/360) x 2pir
Proportion (ratio is same)

4. Volume of a cube
Long diagonal of solid is equal to diameter of sphere
V = (1/3)pir^2h
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
Both will be same fraction of circle (60 degrees = 1/6 of circle)

5. Sum of Angle formula (regular polygons)
Or
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
A = 1/2bh
(n-2)180 (divide this by n to find individual angle measures)

6. Three properties of tangent lines extending from a point to a circle

7. Area of a rectangle
A = bh (both sides of the rectangle)
D^2 = 4r^2 + h^2 (pythagorean theorem)
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)

8. Main property of a cone
A= pir^2
Right angle formed from height radius and slant
Distance / rate
SA = 2pir^2 + 2pirh

9. a shape drawn around another shape with the tighets fit possible
Circumscribed
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Diameter of sphere is equal to length of cube's side

10. One property any angle inscribed in a semi-cricle has
Distance / rate
The angle is a right angle
D^2 = 4r^2 + h^2 (pythagorean theorem)
Proportion (ratio is same)

11. Surface area of a cube
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
D = sroot3
And
SA = 6s^2

12. Right triangle rotated around one leg
Cone
A = bh (both sides of the rectangle)
x^2 - 2xy + y^2
Total = number of things x average

13. Surface area of a cylinder
Cylinder
SA = 2pir^2 + 2pirh
Original x (1 - rate)^number of changes
A = 1/2bh

14. Volume of a rectangular solid
Sphere (same radii)
A= pir^2
V = lwh
Proportion (ratio is same)

15. Volume of a sphere
(4/3)pir^3
Distance / rate
Total = number of things x average
The angle is a right angle

16. (x+y)(x-y)
Both solids have same diameter
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
x^2 - y^2
C = 2pir (or C = pi x d)

17. Volume of a cylinder
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
V= pir^2h
Total = number of things x average
x^2 + 2xy + y^2

18. In an inequality - what conjunction is used with less than
SA 4pir^2
And
Or
(degree/360) x 2pir

19. Circle rotated around its diameter
Sphere (same radii)
The angle is a right angle
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
D = sroot3

20. Long diagonal of a cylinder
D^2 = 4r^2 + h^2 (pythagorean theorem)
Cylinder
Sum of the area of each face (no definite equation)
V = (1/3)pir^2h

21. (x+y)^2
A = bh (both sides of the rectangle)
Total = number of things x average
Sphere (same radii)
x^2 + 2xy + y^2

22. Area of a triangle (geometry)
((amount change) / (original)) x 100
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
A = 1/2bh
Both solids have same diameter

23. 2 additional properties of a rectangle
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Total = number of things x average
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
Circumscribed

24. Relation between central angle and minor arc
Both will be same fraction of circle (60 degrees = 1/6 of circle)
C = 2pir (or C = pi x d)
Inscribed
Cone

25. What two triangles compose a square?
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
Remainder (note all remainders are always integers)
x^2 - 2xy + y^2

26. Area of a sector
D^2 = 4r^2 + h^2 (pythagorean theorem)
(degree/360) x pir^2
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
A = 1/2absinx (where x is included angle of sides a and b)

27. Area of a triangle (trig)
Proportion (ratio is same)
Cone
Or
A = 1/2absinx (where x is included angle of sides a and b)

28. Relation between inscribed angle and minor arc
Inscribed angle will be half of arc (and therefore half of central angle)
A = bh (h is hight from base to vertex and creating a right angle)
SA = pirl + pir^2 (where l is slant of cone)
A = 1/2absinx (where x is included angle of sides a and b)

29. Long diagonal of a cube
Or
D = sroot3
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency

30. 4 Properties of a parallelogram
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
F = sroot2
Original x (1 - rate)^number of changes
(degree/360) x pir^2

31. The integer left over after dividing two numbers
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Remainder (note all remainders are always integers)
A = absinx (where x is the angle between sides a and b)
Both solids have same diameter

32. Surface area of a cone
SA = pirl + pir^2 (where l is slant of cone)
Cone
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
A = 1/2bh

33. length of an arc
1. two equal sides 2. two equal angles of those sides
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
(degree/360) x 2pir
C = 2pir (or C = pi x d)

34. Surface area of a pyramid
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
V = (1/3)pir^2h
((amount change) / (original)) x 100
Sum of the area of each face (no definite equation)

35. 2 properties of regular polygon
Both solids have same diameter
(degree/360) x pir^2
1. all sides are same length 2. all angles are same size
D^2 = 4r^2 + h^2 (pythagorean theorem)

36. a shape that is in another shape - placed inside that shape with tightest fit possible
SA = 6s^2
Inscribed
Cylinder
Cone

37. Sphere inscribed in a cylinder
Diameter of sphere is equal to length of cube's side
Inscribed
Sum of the area of each face (no definite equation)
Both solids have same diameter

38. Percent change
And
Right angle formed from height radius and slant
SA 4pir^2
((amount change) / (original)) x 100

39. Volume of a pyramid
((amount change) / (original)) x 100
Diameter of sphere is equal to length of cube's side
V = (1/3)bh (where b is the area of the base figure)
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length

40. (x-y)^2
Sphere (same radii)
x^2 - 2xy + y^2
Inscribed
1. two equal sides 2. two equal angles of those sides

41. Cylinder inscribed in a sphere

42. Time =
(n-2)180 (divide this by n to find individual angle measures)
A = h/2 (b1 + b2)
Diameter of sphere is equal to length of cube's side
Distance / rate

43. Circumference of a circle
C = 2pir (or C = pi x d)
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Proportion (ratio is same)
Original x (1 - rate)^number of changes

44. Isosceles triangle rotated around axis of symmetry
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Cone
(degree/360) x pir^2
Sphere (same radii)

45. Percent increase
SA 4pir^2
Right angle formed from height radius and slant
Original x (1 + rate)^number of changes
Sphere (same radii)

46. What do you use to solve for indirect variation?
1. two equal sides 2. two equal angles of those sides
(n-2)180 (divide this by n to find individual angle measures)
Multiplication (product is same)
Both will be same fraction of circle (60 degrees = 1/6 of circle)

47. In an inequality - what conjunction is used with greater than
V = s^3
Sum of the area of each face (no definite equation)
Or
(degree/360) x pir^2

48. Area of a parallelogram (geometry)
F = sroot2
A = absinx (where x is the angle between sides a and b)
(degree/360) x pir^2
A = bh (h is hight from base to vertex and creating a right angle)

49. What 2 properties does an isosceles triangle have?
Both solids have same diameter
1. two equal sides 2. two equal angles of those sides
A = bh (h is hight from base to vertex and creating a right angle)
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea

50. Percent decrease
Original x (1 - rate)^number of changes
x^2 - 2xy + y^2
D = sroot3
Total = number of things x average