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SAT Math Subject Test 1 And 2

Subjects : sat, math

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Surface area of a rectangular solid
1. all sides are same length 2. all angles are same size
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
SA = 2lw + 2hw + 2lh
V = lwh

2. Surface area of a cube
((amount change) / (original)) x 100
SA = pirl + pir^2 (where l is slant of cone)
SA = 6s^2
Inscribed

3. a shape drawn around another shape with the tighets fit possible
Right angle formed from height radius and slant
SA = 2lw + 2hw + 2lh
Circumscribed
1. two equal sides 2. two equal angles of those sides

4. Three properties of tangent lines extending from a point to a circle

5. 4 Properties of a parallelogram
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
A = bh (both sides of the rectangle)
(n-2)180 (divide this by n to find individual angle measures)
x^2 - 2xy + y^2

6. Area of a sector
(degree/360) x pir^2
V = lwh
V = (1/3)bh (where b is the area of the base figure)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2

7. Area of a rectangle
A = bh (both sides of the rectangle)
(degree/360) x 2pir
((amount change) / (original)) x 100
V= pir^2h

8. Main property of a cone
SA = 2lw + 2hw + 2lh
Right angle formed from height radius and slant
(degree/360) x 2pir
Prime number (2 is only even prime number - 1 and 0 are not prime)

9. An integer that has exactly two distinct factors: itself and 1
V = (1/3)bh (where b is the area of the base figure)
A= pir^2
Prime number (2 is only even prime number - 1 and 0 are not prime)
((amount change) / (original)) x 100

10. In an inequality - what conjunction is used with less than
And
Total = number of things x average
Diameter of sphere is equal to length of cube's side
Or

11. Percent change
x^2 - 2xy + y^2
((amount change) / (original)) x 100
Diameter of sphere is equal to length of cube's side
Multiplication (product is same)

12. Percent increase
Original x (1 + rate)^number of changes
A = 1/2absinx (where x is included angle of sides a and b)
D = sroot3
SA = 2pir^2 + 2pirh

13. Surface area of a cylinder
Multiplication (product is same)
SA = 2pir^2 + 2pirh
A = absinx (where x is the angle between sides a and b)
F = sroot2

14. Circumference of a circle
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
D = sroot3
C = 2pir (or C = pi x d)

15. Relation between inscribed angle and minor arc
SA 4pir^2
Inscribed
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
Inscribed angle will be half of arc (and therefore half of central angle)

16. Time =
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
Distance / rate
Proportion (ratio is same)
(degree/360) x 2pir

17. Face diagonal of a cube
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
1. two equal sides 2. two equal angles of those sides
SA = 2pir^2 + 2pirh
F = sroot2

18. Cube or rectangular solid inscribed in a sphere
Long diagonal of solid is equal to diameter of sphere
SA = 2pir^2 + 2pirh
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
V= pir^2h

19. (x+y)^2
A= pir^2
V = lwh
x^2 + 2xy + y^2
A = h/2 (b1 + b2)

20. length of an arc
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
V = lwh
(degree/360) x 2pir
1. two equal sides 2. two equal angles of those sides

21. Area of a circle
A= pir^2
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
SA 4pir^2

22. Surface area of a pyramid
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
(degree/360) x pir^2
Both solids have same diameter
Sum of the area of each face (no definite equation)

23. 2 additional properties of a rectangle
V = (1/3)bh (where b is the area of the base figure)
(n-2)180 (divide this by n to find individual angle measures)
Prime number (2 is only even prime number - 1 and 0 are not prime)
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length

24. What do you use to solve for indirect variation?
SA = pirl + pir^2 (where l is slant of cone)
Multiplication (product is same)
A = bh (h is hight from base to vertex and creating a right angle)
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

25. Volume of a cube
Circumscribed
Inscribed angle will be half of arc (and therefore half of central angle)
V = (1/3)pir^2h
(degree/360) x pir^2

26. a shape that is in another shape - placed inside that shape with tightest fit possible
Inscribed
(n-2)180 (divide this by n to find individual angle measures)
V = (1/3)pir^2h
Remainder (note all remainders are always integers)

27. Relation between central angle and minor arc
Proportion (ratio is same)
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Original x (1 + rate)^number of changes
V = (1/3)bh (where b is the area of the base figure)

28. Volume of a rectangular solid
x^2 + 2xy + y^2
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
Distance / rate
V = lwh

29. Percent decrease
A = bh (both sides of the rectangle)
Cone
Sphere (same radii)
Original x (1 - rate)^number of changes

30. Area of a triangle (geometry)
V = (1/3)pir^2h
Proportion (ratio is same)
A = 1/2bh
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency

31. Long diagonal of a cube
Long diagonal of solid is equal to diameter of sphere
D = sroot3
A = absinx (where x is the angle between sides a and b)
Or

32. Sphere inscribed in a cylinder
Both solids have same diameter
x^2 - y^2
1. two equal sides 2. two equal angles of those sides
Cone

33. Area of a parallelogram (geometry)
C = 2pir (or C = pi x d)
A = 1/2bh
Both will be same fraction of circle (60 degrees = 1/6 of circle)
A = bh (h is hight from base to vertex and creating a right angle)

34. Cylinder inscribed in a sphere

35. Volume of a pyramid
V = (1/3)bh (where b is the area of the base figure)
A= pir^2
x^2 - 2xy + y^2
(n-2)180 (divide this by n to find individual angle measures)

36. Area of a trapezoid
Both solids have same diameter
A = h/2 (b1 + b2)
A= pir^2
C = 2pir (or C = pi x d)

37. One property any angle inscribed in a semi-cricle has
A = 1/2bh
Inscribed
The angle is a right angle
x^2 - 2xy + y^2

38. Volume of a cylinder
D = sroot3
V= pir^2h
Diameter of sphere is equal to length of cube's side
Proportion (ratio is same)

39. What do you use to solve for direct variation?
V= pir^2h
1. all sides are same length 2. all angles are same size
Proportion (ratio is same)
A = 1/2bh

40. Long diagonal of a rectangular solid
Right angle formed from height radius and slant
Circumscribed
Cone
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

41. Sphere inscribed in a cube

42. What two triangles compose a square?
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
(degree/360) x pir^2
Total = number of things x average
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2

43. Long diagonal of a cylinder
x^2 - 2xy + y^2
A = bh (h is hight from base to vertex and creating a right angle)
D^2 = 4r^2 + h^2 (pythagorean theorem)
Multiplication (product is same)

44. 2 properties of regular polygon
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Both will be same fraction of circle (60 degrees = 1/6 of circle)
1. all sides are same length 2. all angles are same size
Cone

45. Sum of Angle formula (regular polygons)
x^2 + 2xy + y^2
Sphere (same radii)
(n-2)180 (divide this by n to find individual angle measures)
SA = 2pir^2 + 2pirh

46. Surface area of a cone
A = absinx (where x is the angle between sides a and b)
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
SA = pirl + pir^2 (where l is slant of cone)

47. Isosceles triangle rotated around axis of symmetry
Cone
Cylinder
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
SA = 6s^2

48. Two equations for Area of a square
A = absinx (where x is the angle between sides a and b)
Right angle formed from height radius and slant
Inscribed
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

49. Circle rotated around its diameter
Cylinder
A= pir^2
V = (1/3)bh (where b is the area of the base figure)
Sphere (same radii)

50. Right triangle rotated around one leg
Cone
Right angle formed from height radius and slant
Inscribed angle will be half of arc (and therefore half of central angle)
V = s^3