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SAT Math Subject Test 1 And 2

Subjects : sat, math

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. Volume of a cube
Multiplication (product is same)
SA = 6s^2
Original x (1 - rate)^number of changes
V = s^3

2. a shape drawn around another shape with the tighets fit possible
(degree/360) x 2pir
Circumscribed
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
V= pir^2h

3. Time =
Inscribed angle will be half of arc (and therefore half of central angle)
SA = 2lw + 2hw + 2lh
Proportion (ratio is same)
Distance / rate

4. Volume of a pyramid
D^2 = 4r^2 + h^2 (pythagorean theorem)
A = bh (both sides of the rectangle)
SA = 2lw + 2hw + 2lh
V = (1/3)bh (where b is the area of the base figure)

5. Area of a trapezoid
F = sroot2
D^2 = 4r^2 + h^2 (pythagorean theorem)
A = h/2 (b1 + b2)
Total = number of things x average

6. Percent change
Right angle formed from height radius and slant
((amount change) / (original)) x 100
The angle is a right angle
SA = 2lw + 2hw + 2lh

7. What do you use to solve for indirect variation?
((amount change) / (original)) x 100
SA = pirl + pir^2 (where l is slant of cone)
Multiplication (product is same)
V= pir^2h

8. 4 Properties of a parallelogram
Prime number (2 is only even prime number - 1 and 0 are not prime)
Cone
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
A = bh (h is hight from base to vertex and creating a right angle)

9. Circle rotated around its diameter
A = h/2 (b1 + b2)
V= pir^2h
(degree/360) x pir^2
Sphere (same radii)

10. Area of a parallelogram (trig)
Long diagonal of solid is equal to diameter of sphere
A= pir^2
A = absinx (where x is the angle between sides a and b)
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea

11. Long diagonal of a cube
SA 4pir^2
(n-2)180 (divide this by n to find individual angle measures)
D = sroot3
Cylinder

12. Circumference of a circle
(4/3)pir^3
C = 2pir (or C = pi x d)
Inscribed
Cone

13. Cube or rectangular solid inscribed in a sphere
x^2 + 2xy + y^2
Long diagonal of solid is equal to diameter of sphere
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
(4/3)pir^3

14. Volume of a cylinder
Cone
Inscribed
V= pir^2h
A = bh (h is hight from base to vertex and creating a right angle)

15. Surface area of a pyramid
Sum of the area of each face (no definite equation)
V = (1/3)pir^2h
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
V = (1/3)bh (where b is the area of the base figure)

16. The integer left over after dividing two numbers
x^2 - 2xy + y^2
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
Remainder (note all remainders are always integers)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

17. One property any angle inscribed in a semi-cricle has
Cylinder
V= pir^2h
(4/3)pir^3
The angle is a right angle

18. 2 additional properties of a rectangle
1. all sides are same length 2. all angles are same size
A = 1/2bh
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
SA = 2pir^2 + 2pirh

19. Percent increase
Proportion (ratio is same)
Prime number (2 is only even prime number - 1 and 0 are not prime)
Original x (1 + rate)^number of changes
((amount change) / (original)) x 100

20. length of an arc
Cone
(degree/360) x 2pir
D^2 = 4r^2 + h^2 (pythagorean theorem)
Long diagonal of solid is equal to diameter of sphere

21. Sum of Angle formula (regular polygons)
(degree/360) x 2pir
Sum of the area of each face (no definite equation)
A = absinx (where x is the angle between sides a and b)
(n-2)180 (divide this by n to find individual angle measures)

22. Area of a rectangle
Distance / rate
1. two equal sides 2. two equal angles of those sides
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
A = bh (both sides of the rectangle)

23. Area of a parallelogram (geometry)
1. all sides are same length 2. all angles are same size
A = bh (h is hight from base to vertex and creating a right angle)
V = lwh
Sphere (same radii)

24. Long diagonal of a cylinder
(degree/360) x 2pir
D^2 = 4r^2 + h^2 (pythagorean theorem)
V = s^3
Cone

25. a shape that is in another shape - placed inside that shape with tightest fit possible
The angle is a right angle
Prime number (2 is only even prime number - 1 and 0 are not prime)
Inscribed
V = (1/3)pir^2h

26. Cylinder inscribed in a sphere

27. Sphere inscribed in a cube

28. Area of a triangle (trig)
A = 1/2absinx (where x is included angle of sides a and b)
V = (1/3)pir^2h
Long diagonal of solid is equal to diameter of sphere
Total = number of things x average

29. An integer that has exactly two distinct factors: itself and 1
Circumscribed
Prime number (2 is only even prime number - 1 and 0 are not prime)
A = bh (h is hight from base to vertex and creating a right angle)
SA 4pir^2

30. Surface area of a rectangular solid
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Right angle formed from height radius and slant
SA = 2lw + 2hw + 2lh

31. Area of a circle
A= pir^2
(degree/360) x pir^2
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
(4/3)pir^3

32. In an inequality - what conjunction is used with greater than
1. two equal sides 2. two equal angles of those sides
Multiplication (product is same)
Or
(4/3)pir^3

33. Volume of a rectangular solid
V = lwh
V = (1/3)pir^2h
A = absinx (where x is the angle between sides a and b)
Cone

34. Relation between central angle and minor arc
1. all sides are same length 2. all angles are same size
V = lwh
Both will be same fraction of circle (60 degrees = 1/6 of circle)
SA = 2pir^2 + 2pirh

35. Volume of a sphere
1. two equal sides 2. two equal angles of those sides
Distance / rate
(4/3)pir^3
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2

36. Average pie
Remainder (note all remainders are always integers)
Both solids have same diameter
Total = number of things x average
Original x (1 + rate)^number of changes

37. Two equations for Area of a square
Cone
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)

38. Right triangle rotated around one leg
Cone
V= pir^2h
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Long diagonal of solid is equal to diameter of sphere

39. Volume of a cube
C = 2pir (or C = pi x d)
A = bh (h is hight from base to vertex and creating a right angle)
V = (1/3)pir^2h
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

40. Isosceles triangle rotated around axis of symmetry
Multiplication (product is same)
Diameter of sphere is equal to length of cube's side
Cone
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)

41. In an inequality - what conjunction is used with less than
And
Cylinder
(degree/360) x pir^2
A = 1/2absinx (where x is included angle of sides a and b)

42. Long diagonal of a rectangular solid
x^2 - 2xy + y^2
SA = 2lw + 2hw + 2lh
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
Remainder (note all remainders are always integers)

43. (x-y)^2
V= pir^2h
A = 1/2absinx (where x is included angle of sides a and b)
(degree/360) x 2pir
x^2 - 2xy + y^2

44. (x+y)(x-y)
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
x^2 - y^2
Or
Prime number (2 is only even prime number - 1 and 0 are not prime)

45. Relation between inscribed angle and minor arc
SA = 2lw + 2hw + 2lh
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
The angle is a right angle
Inscribed angle will be half of arc (and therefore half of central angle)

46. What do you use to solve for direct variation?
D^2 = 4r^2 + h^2 (pythagorean theorem)
Proportion (ratio is same)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
SA = 2pir^2 + 2pirh

47. Percent decrease
Original x (1 - rate)^number of changes
SA = 6s^2
Sum of the area of each face (no definite equation)
A = bh (both sides of the rectangle)

48. Main property of a cone
Right angle formed from height radius and slant
Cylinder
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
SA = 2lw + 2hw + 2lh

49. Rectangle rotated around a central line or one side
Sphere (same radii)
Proportion (ratio is same)
Cylinder
The angle is a right angle

50. What 2 properties does an isosceles triangle have?
1. two equal sides 2. two equal angles of those sides
C = 2pir (or C = pi x d)
A = bh (both sides of the rectangle)
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)

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SAT Math Subject Test 1 And 2

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