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Test your basic knowledge |
SAT Math Subject Test 1 And 2
Start Test
Study First
Subjects
:
sat
,
math
Instructions:
Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Surface area of a cube
1. two equal sides 2. two equal angles of those sides
SA = 2lw + 2hw + 2lh
SA = 6s^2
(4/3)pir^3
2. Area of a trapezoid
Prime number (2 is only even prime number - 1 and 0 are not prime)
A= pir^2
Distance / rate
A = h/2 (b1 + b2)
3. An integer that has exactly two distinct factors: itself and 1
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
D^2 = 4r^2 + h^2 (pythagorean theorem)
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
Prime number (2 is only even prime number - 1 and 0 are not prime)
4. Volume of a cube
Sphere (same radii)
1. two equal sides 2. two equal angles of those sides
Remainder (note all remainders are always integers)
V = s^3
5. length of an arc
A = 1/2bh
V = s^3
C = 2pir (or C = pi x d)
(degree/360) x 2pir
6. One property any angle inscribed in a semi-cricle has
The angle is a right angle
Sum of the area of each face (no definite equation)
(degree/360) x pir^2
Original x (1 - rate)^number of changes
7. Sphere inscribed in a cylinder
A = 1/2bh
Both solids have same diameter
Inscribed
Inscribed angle will be half of arc (and therefore half of central angle)
8. Long diagonal of a rectangular solid
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
x^2 - y^2
Both will be same fraction of circle (60 degrees = 1/6 of circle)
Circumscribed
9. Rectangle rotated around a central line or one side
Cone
Cylinder
Remainder (note all remainders are always integers)
x^2 - y^2
10. a shape that is in another shape - placed inside that shape with tightest fit possible
Inscribed
A = absinx (where x is the angle between sides a and b)
x^2 - y^2
SA 4pir^2
11. What do you use to solve for indirect variation?
Sum of the area of each face (no definite equation)
Multiplication (product is same)
(degree/360) x 2pir
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
12. (x+y)(x-y)
x^2 - 2xy + y^2
x^2 - y^2
(degree/360) x pir^2
SA 4pir^2
13. Area of a parallelogram (geometry)
A = bh (h is hight from base to vertex and creating a right angle)
D^2 = 4r^2 + h^2 (pythagorean theorem)
V = (1/3)pir^2h
1. two equal sides 2. two equal angles of those sides
14. Area of a rectangle
Remainder (note all remainders are always integers)
Inscribed angle will be half of arc (and therefore half of central angle)
A = bh (both sides of the rectangle)
Prime number (2 is only even prime number - 1 and 0 are not prime)
15. 2 properties of regular polygon
Original x (1 + rate)^number of changes
1. all sides are same length 2. all angles are same size
C = 2pir (or C = pi x d)
Cone
16. Area of a circle
(degree/360) x pir^2
C = 2pir (or C = pi x d)
V = s^3
A= pir^2
17. In an inequality - what conjunction is used with greater than
Or
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
Distance / rate
And
18. (x-y)^2
x^2 - 2xy + y^2
A = absinx (where x is the angle between sides a and b)
1. distances from points of tangency will be equal on both sides 2. Angle created will be equal at circle's center 3. Will create right angles on both sides at point of tangency
Original x (1 - rate)^number of changes
19. a shape drawn around another shape with the tighets fit possible
Circumscribed
A = absinx (where x is the angle between sides a and b)
Original x (1 - rate)^number of changes
Both will be same fraction of circle (60 degrees = 1/6 of circle)
20. Two equations for Area of a square
SA = 2pir^2 + 2pirh
SA = 6s^2
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
A = bh (both sides of the rectangle)
21. Surface area of a cylinder
SA = 2pir^2 + 2pirh
A = bh (h is hight from base to vertex and creating a right angle)
A = 1/2absinx (where x is included angle of sides a and b)
D^2 = 4r^2 + h^2 (pythagorean theorem)
22. Volume of a cube
Prime number (2 is only even prime number - 1 and 0 are not prime)
SA = 6s^2
((amount change) / (original)) x 100
V = (1/3)pir^2h
23. Circle rotated around its diameter
Sphere (same radii)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
The angle is a right angle
Diameter of sphere is equal to length of cube's side
24. Area of a triangle (trig)
A = 1/2absinx (where x is included angle of sides a and b)
SA 4pir^2
Diameter of sphere is equal to length of cube's side
1. two equal sides 2. two equal angles of those sides
25. Cube or rectangular solid inscribed in a sphere
Long diagonal of solid is equal to diameter of sphere
And
A = absinx (where x is the angle between sides a and b)
SA 4pir^2
26. Percent change
((amount change) / (original)) x 100
The angle is a right angle
D^2 = 4r^2 + h^2 (pythagorean theorem)
V = (1/3)bh (where b is the area of the base figure)
27. Surface area of a pyramid
V = (1/3)pir^2h
A = 1/2bh
Sum of the area of each face (no definite equation)
Circumscribed
28. Area of a sector
V= pir^2h
(degree/360) x pir^2
SA 4pir^2
Multiplication (product is same)
29. Volume of a rectangular solid
Multiplication (product is same)
(4/3)pir^3
V = lwh
(degree/360) x 2pir
30. 2 additional properties of a rectangle
D^2 = 4r^2 + h^2 (pythagorean theorem)
A = h/2 (b1 + b2)
1. each of the four interior angles measures 90 degrees 2. diagonals of a rectangle are of equal length
A= pir^2
31. Relation between central angle and minor arc
(n-2)180 (divide this by n to find individual angle measures)
Both will be same fraction of circle (60 degrees = 1/6 of circle)
x^2 + 2xy + y^2
Circumscribed
32. Volume of a pyramid
Sphere (same radii)
(4/3)pir^3
A = absinx (where x is the angle between sides a and b)
V = (1/3)bh (where b is the area of the base figure)
33. Sum of Angle formula (regular polygons)
(n-2)180 (divide this by n to find individual angle measures)
Diameter of sphere is equal to length of cube's side
Inscribed angle will be half of arc (and therefore half of central angle)
SA = 2pir^2 + 2pirh
34. Isosceles triangle rotated around axis of symmetry
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
SA = 2lw + 2hw + 2lh
Cone
C = 2pir (or C = pi x d)
35. Volume of a sphere
Sphere's diameter is equal to diagonal of rectangle formed by cylinder's height and diameter (other words - diagonal of cylinder equals sphere's diameter)
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
(4/3)pir^3
Cylinder
36. Main property of a cone
((amount change) / (original)) x 100
Right angle formed from height radius and slant
Total = number of things x average
(degree/360) x pir^2
37. Cylinder inscribed in a sphere
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38. Circumference of a circle
C = 2pir (or C = pi x d)
Prime number (2 is only even prime number - 1 and 0 are not prime)
x^2 - 2xy + y^2
V = lwh
39. Long diagonal of a cylinder
1. two equal sides 2. two equal angles of those sides
Original x (1 + rate)^number of changes
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
D^2 = 4r^2 + h^2 (pythagorean theorem)
40. 4 Properties of a parallelogram
1. opposite angles in a parallelogram are equal 2. adjacent angles in a parallelogram are supplementary; they add up to 180 degrees (think transversal) 3. opposite sides in a parallelogram are of equal length 4. diagonals of a parallelogram bisect ea
(degree/360) x 2pir
Original x (1 + rate)^number of changes
Cone
41. In an inequality - what conjunction is used with less than
And
Right angle formed from height radius and slant
Total = number of things x average
Original x (1 + rate)^number of changes
42. What 2 properties does an isosceles triangle have?
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
1. two equal sides 2. two equal angles of those sides
The angle is a right angle
V = s^3
43. Area of a triangle (geometry)
Both solids have same diameter
A = absinx (where x is the angle between sides a and b)
The angle is a right angle
A = 1/2bh
44. Percent decrease
Sum of the area of each face (no definite equation)
1. all sides are same length 2. all angles are same size
SA = pirl + pir^2 (where l is slant of cone)
Original x (1 - rate)^number of changes
45. Sphere inscribed in a cube
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46. What two triangles compose a square?
V= pir^2h
Diameter of sphere is equal to length of cube's side
Multiplication (product is same)
Two sets of 45-45-90 right triangles (with side measures of x - x - and xroot2
47. Right triangle rotated around one leg
A = bh (both sides of the rectangle)
F = sroot2
Cone
1. two equal sides 2. two equal angles of those sides
48. Long diagonal of a cube
SA = 6s^2
F = sroot2
D = sroot3
A = 1/2absinx (where x is included angle of sides a and b)
49. Average pie
V = s^3
A = s^2 A = d^2/2 (where d is long diagonal 45 45 90 triangle)
Total = number of things x average
V = lwh
50. Surface area of a cone
D^2 = a^2 + b^2 + c^2 (Super Pythagorean Theorem)
A = bh (both sides of the rectangle)
A = 1/2absinx (where x is included angle of sides a and b)
SA = pirl + pir^2 (where l is slant of cone)