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Test your basic knowledge |
AP Calculus 2
Start Test
Study First
Subjects
:
math
,
ap
,
calculus
Instructions:
Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. tan 2p
1/v(1-x^2 )
1/(|x| v(x^2-1))
0
-v3/2
2. sin 5p/4
-v3/2
f(x) = u/v AND f'(x) = vu'-uv'/v^2 (lo de hi minus hi de lo/ lo squared)
1/(u ln a ) du/dx
-v2/2
3. sin p/2
1
1/2
v3
v3/3
4. Deriv of sec^(-1)x
0
1/(|x| v(x^2-1))
1
-v3
5. tan 5p/3
v3/3
1
-v3
v3/3
6. sin p/6
1/2
1/(1+x^2 )
-1
-v3
7. cos p/6
1/v(1-x^2 )
v3/2
-v2/2
-v2/2
8. cos p/2
0
-v3
v3/3
-1/2
9. cos 2p/3
sec^2x
f^' (a)=lim-(x?a)??(f(x)-f(a))/(x-a)? - It is finding the slope of the tangent line at a particular x-value
-1/2
-v3/2
10. tan 5p/4
v2/2
v3/2
1
-v2/2
11. cos 5p/3
1/(1+x^2 )
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
-v2/2
1/2
12. sin 4p/3
sec^2x
-csc^2x
-v3/2
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
13. sin 2p/3
v3/2
tanxsecx
e^x
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
14. Deriv of f(x)=secx is?
tanxsecx
-v3/3
0
slope of the tangent line
15. cos 5p/4
-v2/2
0
v3/2
f(x) = u/v AND f'(x) = vu'-uv'/v^2 (lo de hi minus hi de lo/ lo squared)
16. Explicit differentiation
-1
1/(u ln a ) du/dx
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
1
17. Deriv of f(x)=sinx is?
cosx
v2/2
undefined
-v2/2
18. Deriv of e^x
e^x
-1/2
1
v2/2
19. sin 3p/4
-1/2
v2/2
v3
1/u du/dx
20. sin 3p/2
v3/2
-cscxcotx
-1
0
21. sin 7p/6
0
-1/(1+x^2 )
1/2
-1/2
22. tan 7p/6
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
v3/3
0
a^u lna du/dx
23. Deriv of cot^(-1)x
-1/2
-1/(1+x^2 )
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
-cscxcotx
24. What is the Alternate definition of a derivative and what does it find?
25. cos 5p/6
v2/2
1
-1/2
-v3/2
26. tan 3p/2
-1/2
0
undefined
-1
27. tan p
0
-1/2
1
-v3
28. sin p
f(x) = (u)(v) AND f'(x) = u'v + v'u
tanxsecx
0
v3/2
29. cos p/4
1) find the derivative of both sides of the function 2) put all terms with a y prime on the same side (y prime aka derivative of y) 3) factor out a y 4) solve for y prime
-1
v2/2
-1/v(1-x^2 )
30. derivative
-v3
-csc^2x
slope of the tangent line
-1/2
31. cos 7p/6
not clear; when you can solve for y as a function of x - EX) y^3+y^2-5y-x^2=4
-v3/2
v3
1/2
32. sin p/4
v2/2
a^u lna du/dx
f(x) = (u)(v) AND f'(x) = u'v + v'u
-1/v(1-x^2 )
33. Deriv of tan^(-1)x
-1
-1/2
1/(1+x^2 )
1
34. Deriv of a^u
v2/2
-1/v(1-x^2 )
a^u lna du/dx
-v2/2
35. Deriv of f(x)=cotx is?
-1
f^' (a)=lim-(x?a)??(f(x)-f(a))/(x-a)? - It is finding the slope of the tangent line at a particular x-value
-v2/2
-csc^2x
36. Deriv of f(x)=cosx is?
e^x
-sinx
v3/2
-v2/2
37. Deriv of f(x)=csc is?
-v2/2
-cscxcotx
-1/v(1-x^2 )
-v3
38. tan 2p/3
v3/2
f(x) = u/v AND f'(x) = vu'-uv'/v^2 (lo de hi minus hi de lo/ lo squared)
-v3
1/2
39. Deriv of log_au=
1/(u ln a ) du/dx
-csc^2x
-v2/2
v2/2
40. tan p/6
-v3/2
1/(u ln a ) du/dx
0
v3/3
41. cos 11p/6
-1/(|x| v(x^2-1))
-v2/2
v3/2
1
42. Deriv of ln u
-v2/2
-v3/3
1/u du/dx
1/2
43. What is the quotient rule?
44. cos 7p/4
v2/2
slope of the tangent line
-sinx
Deriv of Outside(Inside)*Deriv of Inside - It can be used anytime
45. cos p/3
v3
1
1/2
slope of the tangent line
46. Deriv of sin^(-1)x
1
-1/2
f(x) = (u)(v) AND f'(x) = u'v + v'u
1/v(1-x^2 )
47. Deriv of csc^(-1)x
-1/(1+x^2 )
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
-1/(|x| v(x^2-1))
v3/2
48. tan p/4
1
1/2
-v3
-v3/3
49. sin 11p/6
-1/2
-v2/2
1/2
1
50. When do derivatives not exist?
1/2
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
-1/(1+x^2 )
1/(|x| v(x^2-1))