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Test your basic knowledge |
AP Calculus 2
Start Test
Study First
Subjects
:
math
,
ap
,
calculus
Instructions:
Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. tan p/3
-v3/2
v3
v3/2
0
2. cos 5p/3
1/v(1-x^2 )
1) find the derivative of both sides of the function 2) put all terms with a y prime on the same side (y prime aka derivative of y) 3) factor out a y 4) solve for y prime
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
1/2
3. tan 7p/4
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
-1
a^u lna du/dx
not clear; when you can solve for y as a function of x - EX) y^3+y^2-5y-x^2=4
4. sin 2p
1/2
e^x
0
-v3/3
5. cos 7p/6
-v3/3
-v3/2
1
v3
6. cos p/2
-1/2
0
-v3/2
-v3
7. What is the product rule?
8. tan 5p/3
-1
-v3
a^u lna du/dx
1/u du/dx
9. sin 3p/4
v3/2
1/u du/dx
v2/2
0
10. sin 5p/4
-v2/2
1
-1/2
cosx
11. Deriv of f(x)=tanx is?
not clear; when you can solve for y as a function of x - EX) y^3+y^2-5y-x^2=4
-1
sec^2x
v3/2
12. tan 4p/3
-1/2
-v2/2
-1
v3
13. tan 2p
0
-1
1
1/(u ln a ) du/dx
14. derivative
slope of the tangent line
1
1) find the derivative of both sides of the function 2) put all terms with a y prime on the same side (y prime aka derivative of y) 3) factor out a y 4) solve for y prime
-1/(1+x^2 )
15. Deriv of f(x)=cotx is?
-sinx
-csc^2x
-v3
f^' (x)=lim-(h?0)??(f(x+h)-f(x))/h?
16. cos 2p/3
v3
-csc^2x
1/u du/dx
-1/2
17. tan 5p/4
-sinx
1
-1/2
-v2/2
18. tan p/4
Deriv of Outside(Inside)*Deriv of Inside - It can be used anytime
1/v(1-x^2 )
1
f^' (x)=lim-(h?0)??(f(x+h)-f(x))/h?
19. Deriv of f(x)=secx is?
-1
v3/2
tanxsecx
-1/(|x| v(x^2-1))
20. tan p/2
-v3/3
undefined
f^' (a)=lim-(x?a)??(f(x)-f(a))/(x-a)? - It is finding the slope of the tangent line at a particular x-value
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
21. tan 5p/6
1/u du/dx
-1/2
-v3/2
-v3/3
22. sin 5p/3
f^' (x)=lim-(h?0)??(f(x+h)-f(x))/h?
v3/2
1/(|x| v(x^2-1))
-v3/2
23. Deriv of tan^(-1)x
0
1/(1+x^2 )
v3
1/2
24. tan 2p/3
-v3/3
-v3/3
e^x
-v3
25. cos 5p/6
0
-v3/2
-1/2
-v3/3
26. cos p/6
undefined
v3/2
v2/2
-v2/2
27. Deriv of sin^(-1)x
-v2/2
1/v(1-x^2 )
1/(|x| v(x^2-1))
-1/2
28. What is the Chain Rule? When can it be used?
1
-csc^2x
-v3/2
Deriv of Outside(Inside)*Deriv of Inside - It can be used anytime
29. Guidelines for implicit differentiation
-v3/3
1) find the derivative of both sides of the function 2) put all terms with a y prime on the same side (y prime aka derivative of y) 3) factor out a y 4) solve for y prime
v3/2
-1/v(1-x^2 )
30. sin 7p/6
-1/2
1/v(1-x^2 )
-v3/2
-v3/3
31. Deriv of f(x)=csc is?
-1/2
-v2/2
-cscxcotx
-1/(|x| v(x^2-1))
32. Deriv of ln u
1/u du/dx
1
slope of the tangent line
1/2
33. Deriv of sec^(-1)x
1/(|x| v(x^2-1))
sec^2x
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
undefined
34. tan p/6
1/v(1-x^2 )
1)At a "spot" of discontinuity (pt.(hole) - infinite(VA) - jump) 2)At a corner 3)At a cusp(sharp pt.) 4)At a vertical tangent line
1
v3/3
35. What is the quotient rule?
36. sin p/3
1/2
0
v3/2
-v3/2
37. Deriv of cot^(-1)x
-1/(1+x^2 )
-csc^2x
1
-v3/3
38. tan 3p/4
1
-1
1
-sinx
39. Deriv of a^u
-v3/2
1
a^u lna du/dx
-v3/2
40. what is the the limit definition of a derivative and what does it find?
41. sin 3p/2
1/(u ln a ) du/dx
1
-1
f(x) = (u)(v) AND f'(x) = u'v + v'u
42. Deriv of f(x)=cosx is?
0
-sinx
v3/2
-1
43. Explicit differentiation
1/2
undefined
very clear; the variable y is explicitly written as a function of x and it only works when you can solve for the function explicitly E.g. y=3x^2-5
1
44. sin p/6
0
v2/2
-cscxcotx
1/2
45. sin 4p/3
f(x) = (u)(v) AND f'(x) = u'v + v'u
-v3/2
-1/2
1/2
46. cos p/4
v2/2
-csc^2x
v3/2
-1/2
47. sin 5p/6
1/2
0
-v3/3
Deriv of Outside(Inside)*Deriv of Inside - It can be used anytime
48. cos 4p/3
1
-1/2
1/(1+x^2 )
not clear; when you can solve for y as a function of x - EX) y^3+y^2-5y-x^2=4
49. cos 7p/4
v3/2
v2/2
-v3/2
f(x) = (u)(v) AND f'(x) = u'v + v'u
50. cos 5p/4
-v2/2
-cscxcotx
1/2
undefined