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Test your basic knowledge |
CLEP Pre - Calculus
Start Test
Study First
Subjects
:
clep
,
math
,
calculus
Instructions:
Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. y=2sinxcosx
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2. y=x²e²
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3. p/4
y'(1/8)=66
1/2
arcsec(v2)
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
4. Log4(x)-Log4(x-1)=1/2 x=
arctan 1
2
-v2/2
-v2/2
5. tan p/4
v3/3
x=3
1
Period = pi - Amplitude = 2 - Vertical Shift up 3
6. Log2(2x+5)=Log2(x+6) x=
y'=e/(2vx)
no solution
1
arctan(?v3)
7. -p/3
x=3
arcsin(-
arctan 1
(log64)/3
8. log3 (5x + 7) = 2 x=
no solution
2/5
1/2
2
9. sin p/3
1/2
-v3/3
arctan(?v3)
v3/2
10. sin p/4
arccos(
x=6
v3
v2/2
11. 3³n=27 n=
y'=-2sin²x+2cos²x
ln5+1
1
arccos
12. p/6
2/5
2
2
arcsin
13. cos 3p/4
arcsec(-1)
arccos(
y'(1/8)=0
-v2/2
14. sin p/2
1
v2/2
arcsin(-
106/7
15. 11=3e²n-1 n=
e-1
y'(1/8)=0
(ln4)/2
x=3
16. 3p/4
v2/2
arccos(-
5
1/2
17. cos 5p/4
-v2/2
v2/2
Period = 2pi - Amplitude = 2 - Vertical Shift up 3 - flip over the x-axis
2
18. cosine
The cofunction of sine
y'=14x
-1/2
y'(1/8)=0
19. How do you calculate the amplitude from a set of sinusoidal data?
ln5+1
1/2
y'(1/8)=66
Take the highest minus the lowest value and divide by 2
20. How could you affect the period of a graph made by a tuning fork?
frequency
x=3
arctan(v3)
Get a tuning fork with a different frequency.
21. log22³n
v2/2
arccos(v3)
2
3n
22. log5(5x + 1) = log5(5) x=
4/5
1/2
-v3
1
23. p/3
y'=x²e^x + 2xe^x
-1/2
-1/2
arcsec 2
24. -p/4
1/2
arctan(-1)
arcsin(-1)
period
25. y=x²e^x
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26. tan p/6
v3/3
arccos(-
-v3
3n
27. y=-1/x+2x
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28. p/3
Period = pi - Amplitude = 2 - Vertical Shift up 3
arctan(v3)
arccos 0
1
29. cos 11p/6
(ln4)/2
1
(ln3)/3
v3/2
30. y=-3cos(-3x)+3
Period = 2pi/3 - Vertical Shift up 3 - Amplitude = 3 - flipped over the x and y axis.
U
(ln4)/2
y'=e/(2vx)
31. sin 2p/3
v2/2
v3/2
arcsin 0
x=125
32. 2p/3
1
y'=((cosx)(2x+3)+(x²+3x+5)sinx)/ cos²x
arcsin(-
arccos(-
33. tan 4p/3
v3
v3/3
infinite
Period = 2pi - Amplitude = 2 - Vertical Shift up 3 - flip over the x-axis
34. y=sinp(x²+3x+5)
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35. log28=x
-v3/2
x=3
3n
x=-3
36. 5(6³n)=20 n =
y'(4)=25
3n
3/7
(log64)/3
37. y=3cos(2x)+1
y'=2xe²
Period = pi - Amplitude = 3 - Vertical Shift up 1
arcsec 1
arccos(v3)
38. p/3
arcsin(
-v3/2
frequency
arctan(-v3)
39. y=2e^x+p²
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40. How could you affect the amplitude of a graph made by a tuning fork?
y'=14x
-v3
arcsec 2
Make the sound of the fork louder
41. How many different Sine equations will match the graph of a tuning fork
-v3/3
9
U
infinite
42. log3x=4
x=81
y'=sinp(2x+3)
x=4
-1/2
43. -p/6
e8
arccos(-
The frequency of the tuning fork is smaller.
arcsin(-
44. p/2
arcsin 1
v3/2
Period = pi - Amplitude = 2 - Horizontal Shift 3/2 left
-v2/2
45. undefined
y'=7/x³
-v3/3
arcsin(-3)
arcsin(
46. cos 7p/4
y'=-2sin²x+2cos²x
v2/2
arctan(v3)
arccos(-
47. Ln(2x-1)=3 x=
(e
arcsin(
1
arcsin
48. What is the base of log5125?
y'=1/(2evx)
5
ln5+1
-v2/2
49. y=2sin 2( x +3 )
Period = pi - Amplitude = 2 - Horizontal Shift 3 left
arcsin(-
v3/3
x=81
50. 47n=64 n=
Period = pi - Amplitude = 3 - Vertical Shift up 1
arcsin(-1)
no solution
3/7