Test your basic knowledge |

CLEP Pre - Calculus

Instructions:

Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. y=2cos(3x+pi)
arcsin(
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
v3/3
e8

2. sin p/3
1
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²
v3/2
1

3. cos 7p/6
Make the sound of the fork louder
-1/2
-v3/2
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²

4. 2p/3
1
arcsec(-2)
v2/2
x=3

5. Ln(x)=8 x=
(e
U
e8
arcsec 2

6. 0
arcsec 1
1
Amplitude = 2 - Flip over the x-axis - Frequency = 3/2pi
-v3/2

7. sin 4p/3
arccos 0
x=3
2
-v3/2

8. The reciprocal of the period
y'=2
arcsec 1
0
frequency

9. y=7(x²+9)

10. p/3
arccos(-
arcsin(
-v2/2
v3/2

11. log5x=3
x=125
The cofunction of sine
arccos
2

12. y=cos(1/2x)+1
arcsec(v2)
1/2
Take the highest minus the lowest value and divide by 2
Period = 4pi - Up 1 - amplitude = 1

13. log3 (5x + 7) = 2 x=
-1/2
-v3
arcsec(-v2)
2/5

14. 2 log5125=x
x=6
y'=2e^x
1
-v3/2

15. 4=3e4n+1 n=
arcsin(-
3/7
-1/2
0

16. sin p/6
1/2
Period = 2pi/3 - Vertical Shift up 3 - Amplitude = 3 - flipped over the x and y axis.
(ln4)/2
-v3/2

17. The standard period for Sine is ____ pi
1
arcsec(-2)
2
Arcsine

18. sin p/2
y'=7/x³
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
1/2
1

19. 4+Log(7x)=10 x=
3/7
106/7
-v2/2
-v3/2

20. p/4
arccos(
period
The frequency of the tuning fork is smaller.
Get a tuning fork with a different frequency.

21. If the period of the graph of a tuning fork is larger
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
arcsin(-3)
v3/2
The frequency of the tuning fork is smaller.

22. cos 5p/4
-v3
-v2/2
1
y'=x²e^x + 2xe^x

23. How do you calculate the amplitude from a set of sinusoidal data?
Take the highest minus the lowest value and divide by 2
v2/2
-v2/2
y'=e/(2vx)

24. y=(x²+3x+5)/cosx

25. The inverse of sine
y'=e/(2vx)
Arcsine
The cofunction of sine
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²

26. sin 7p/6
arctan 0
-1/2
arccos
y'=(-14x)/(x²+9)²

27. cos p/4
v3/3
The frequency of the tuning fork is smaller.
v2/2
arcsin(

28. sin 5p/6
1/2
y'=((cosx)(2x+3)+(x²+3x+5)sinx)/ cos²x
v2/2
(ln3)/3

29. 2²n=16 n=
period
y'=((cosx)(2x+3)+(x²+3x+5)sinx)/ cos²x
2
-v2/2

30. undefined
arccos(-2)
arccos
arccos(v3)
3/7

31. y=sin²x+cos²x+2x

32. p
arcsec(-2)
arcsec(-1)
arcsec 1
Amplitude = 2 - Flip over the x-axis - Frequency = 3/2pi

33. tan p/3
arctan(-?v3)
v3/3
Period = pi - Amplitude = 2 - Horizontal Shift 3/2 left
v3

34. -p/2
y'(1/8)=66
y'=7/x³
ln5+1
arcsin(-1)

35. 10e³n-7=23 n=
-v2/2
(ln3)/3
1
arccos(-

36. How could you affect the amplitude of a graph made by a tuning fork?
v2/2
Make the sound of the fork louder
arctan 1
Arcsine

37. sin 3p/2
1
arccos(-
-1
arcsec(-2)

38. y=3cos(2x)+1
y'=((cosx)(2x+3)+(x²+3x+5)sinx)/ cos²x
y'=1/(2evx)
Period = pi - Amplitude = 3 - Vertical Shift up 1
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3

39. y=7/(x²+9)

40. cos 5p/3
-v3/2
1
1/2
Period = 4pi - Up 1 - amplitude = 1

41. tan 5p/6
y'(1/8)=0
-v3/3
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
y'=(2x+3)sinx+cosx(x²+3x+5)

42. sin 7p/4
v3/2
arccos 1
-v2/2
arcsin 2

43. p/3
arccos
1
y'=e/(2vx)
1

44. cos p/3
y'(4)=25
1/2
v2/2
Period = 2pi/3 - Vertical Shift up 3 - Amplitude = 3 - flipped over the x and y axis.

45. cos 11p/6
x=6
3n
arctan 0
v3/2

46. sin 11p/6
Period = pi - Amplitude = 2 - Horizontal Shift 3 left
-v3/3
-1/2
v3

47. y=sinx(x²+3x+5)

48. cos 3p/4
v3
106/7
3n
-v2/2

49. y = -2 sin ( x ) + 3
Period = 2pi - Amplitude = 2 - Vertical Shift up 3 - flip over the x-axis
-1/2
The cofunction of sine
100/3

50. undefined
arccos(-2)
infinite
2
-v3