Instructions:

• Answer 50 questions in 15 minutes.
• If you are not ready to take this test, you can study here.
• Match each statement with the correct term.
• Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. y=sinx(x²+3x+5)

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2. 4=2en+4 n=
y'(1/8)=0
x=3
y'=sinp(2x+3)
no solution


3. y=100vx

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4. y=7/(x²+9)

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5. y=2cos(3x+pi)
Period = pi - Amplitude = 2 - Horizontal Shift 3 left
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
no solution
arccos 1


6. 0
y'=e/(2vx)
v3/2
arccos 1
U


7. tan 7p/6
y'=(2x+3)sinx+cosx(x²+3x+5)
Amplitude = 2 - Flip over the x-axis - Frequency = 3/2pi
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²
v3/3


8. y=(x²+3x+5)/cosx

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9. log327=x
x=3
y'(1/8)=0
2
Make the sound of the fork louder


10. p
arcsec 1
arccos(-1)
y'=2
arctan(?v3)


11. Log2(2x+5)=Log2(x+6) x=
-1/2
arctan(-v3)
1
The cofunction of sine


12. What is the base of log5125?
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
5
e-1
0


13. y=2sin(-x)+3
(e
y'=2
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
v3/2


14. undefined
v2/2
arccos(v3)
no solution
y'=sinp(2x+3)


15. -p/6
arctan(-1)
v3/2
1
arcsin(-


16. tan 5p/3
Period = 2pi - Amplitude = 2 - Vertical Shift up 3 - flip over the x-axis
v2/2
-v3
Make the sound of the fork louder


17. The time it takes to complete on cycle of a triginometric graph
arccos
arcsin(
v2/2
period


18. cos 5p/4
1
-v2/2
-v3/2
arcsec(-v2)


19. sin 7p/6
-1
arcsec(v2)
1
-1/2


20. cos p/4
(e
v2/2
y'=((cosx)(2x+3)+(x²+3x+5)sinx)/ cos²x
arcsec(-2)


21. 5p/6
-v3/3
arcsin(-
arccos(-
y'(1/8)=0


22. The standard period for tangent is ____ pi
arcsin(
2
arccos(-
1


23. p/4
Period = 2pi - Amplitude = 2 - Vertical Shift up 3 - flip over the x-axis
(e
arctan 1
arcsin(-3)


24. How do you calculate the amplitude from a set of sinusoidal data?
Make the sound of the fork louder
arctan(-v3)
arcsin(-
Take the highest minus the lowest value and divide by 2


25. y=sin²x+cos²x+2x

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26. sin p/3
x=3
v3/2
-1/2
-1/2


27. 0
arcsin 0
arcsin(
1
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²


28. p/6
arcsin(
arccos(
arcsin 0
-1/2


29. cos p/3
Arcsine
Period = pi - Amplitude = 2 - Horizontal Shift 3 left
(log64)/3
1/2


30. log3 (5x + 7) = 2 x=
3/7
2
2/5
arcsec(v2)


31. 21=5e^(x-1) - 4 n=
ln5+1
y'=x²e^x + 2xe^x
y'=2p
no solution


32. y=2sin(2x+3)
-1/2
3n
Period = pi - Amplitude = 2 - Horizontal Shift 3/2 left
v2/2


33. If the period of the graph of a tuning fork is larger
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
arcsin(-3)
e-1
The frequency of the tuning fork is smaller.


34. 2p/3
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
arcsec(-2)
arcsec(-v2)
arccos


35. sin 3p/2
-1
1
-v3
arccos(-


36. 3p/4
-1/2
x=3
arcsec(-v2)
(log64)/3


37. y=2sin 2( x +3 )
arcsin(
1
Period = pi - Amplitude = 2 - Horizontal Shift 3 left
x=3


38. y=p³

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39. cosine
-1
1
arcsin 0
The cofunction of sine


40. tan 3p/2
1
arccos 1
U
arccos(-


41. cos 11p/6
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²
v3/2
Get a tuning fork with a different frequency.
arcsec(v2)


42. sin 7p/4
-v2/2
The cofunction of sine
U
1


43. log22³n
arctan(-v3)
Amplitude = 2 - Flip over the x-axis - Frequency = 3/2pi
y'=((cosx)(2x+3)+(x²+3x+5)sinx)/ cos²x
3n


44. p/4
-1
-v3/2
arccos(v3)
arcsec(v2)


45. 11=3e²n-1 n=
(ln4)/2
arccos(-
y'=1/(2evx)
-1/2


46. cos 7p/6
4/5
-v3/2
e-1
e8


47. log3x=4
1/2
x=81
-v3
100/3


48. p/4
arccos(-
arcsin(
v3/2
y'(1/8)=0


49. p/6
arcsec(-1)
arcsin
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
ln5+1


50. y=2e^x+p²

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