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Test your basic knowledge |
CLEP Pre - Calculus
Start Test
Study First
Subjects
:
clep
,
math
,
calculus
Instructions:
Answer 50 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. sin 4p/3
106/7
arcsin 2
y'=(-14x)/(x²+9)²
-v3/2
2. If the period of the graph of a tuning fork is larger
y'=2xe²
The frequency of the tuning fork is smaller.
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
-v3/2
3. undefined
arcsin 2
(ln3)/3
arcsin(
arcsec 1
4. sin 5p/6
arccos(
arccos(-2)
1/2
arcsin(-
5. y=2cos(3x+pi)
arctan 0
v3/2
arctan(v3)
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
6. p/6
-1
Amplitude = 2 - Flip over the x-axis - Frequency = 3/2pi
arctan(?v3)
y'=2
7. 5p/6
arccos(-
1
Period = pi - Amplitude = 2 - Horizontal Shift 3/2 left
y'=e/(2vx)
8. sin 7p/6
y'=((x²+3x+5)(cosx)-sinx(2x+3))/(x²+3x+5)²
-v3/2
-1/2
-v3/3
9. How could you affect the period of a graph made by a tuning fork?
Get a tuning fork with a different frequency.
e-1
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
1
10. 4+Log(7x)=10 x=
arcsec 1
1
106/7
-v3/2
11. y=p³
12. tan 3p/2
The frequency of the tuning fork is smaller.
U
arccos(-
v3/2
13. lne³n
3n
-1
y'=7/x³
infinite
14. p
arccos(-1)
v3/2
(ln3)/3
9
15. -p/4
arctan(-1)
Period = 4pi - Up 1 - amplitude = 1
arctan(?v3)
U
16. y=2sin 2( x +3 )
arcsin(
Period = pi - Amplitude = 2 - Horizontal Shift 3 left
x=4
Period = pi - Amplitude = 2 - Vertical Shift up 3
17. p/3
1
2
(ln3)/3
arcsin(
18. How could you affect the amplitude of a graph made by a tuning fork?
arccos(-
y'(1/8)=66
U
Make the sound of the fork louder
19. y=-2cos(3x)
Amplitude = 2 - Flip over the x-axis - Frequency = 3/2pi
Period = pi - Amplitude = 2 - Vertical Shift up 3
v3/2
U
20. p/4
arcsin(
(ln3)/3
arccos
arcsin(-
21. p/3
arcsin(-
arctan(v3)
arcsec 2
x=3
22. p/2
v2/2
-v3/3
arcsin 1
arcsin(-
23. 0
arccos 1
-1
y'=2p
-1
24. tan 5p/3
-1
The cofunction of sine
-v3
y'(4)=25
25. cos p/3
arccos 0
arcsec(-1)
arcsin(-3)
1/2
26. p/6
U
- sine
arcsin
-1
27. y=2sin(-x)+3
y'=x²e^x + 2xe^x
x=3
-1/2
Period = 2pi - Amplitude = 2 - Up three - Flips over the y-axis
28. 5(6³n)=20 n =
arcsec 1
(log64)/3
Period = 4pi - Up 1 - amplitude = 1
arcsin(
29. y=cosx(x²+3x+5)
30. -p/6
arctan 1
Take the highest minus the lowest value and divide by 2
arcsin(-
y'=-2sin²x+2cos²x
31. y=7(x²+9)
32. y=x²e²
33. 0
arcsin(
3/7
-1
arcsec 1
34. cos 2p
1
Period = pi - Amplitude = 2 - Vertical Shift up 3
arctan(?v3)
arctan 0
35. How do you calculate the amplitude from a set of sinusoidal data?
y'=(2x+3)sinx+cosx(x²+3x+5)
-1
y'(4)=25
Take the highest minus the lowest value and divide by 2
36. 2²n=16 n=
2
-1
Arcsine
0
37. y=x²e^x
38. sin 5p/4
arcsec 1
-1
arccos(
-v2/2
39. p/6
arcsec(-2)
no solution
arccos(
y'=e/(2vx)
40. The inverse of sine
v3/3
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
-1
Arcsine
41. undefined
arccos(-2)
4/5
100/3
Period = 2pi/3 - Amplitude = 2 - Phase Shift pi/3
42. Ln(x)=8 x=
e8
arccos(-
-1
arcsin(-
43. cos 5p/4
-1/2
-v2/2
arctan(-?v3)
x=125
44. sin 3p/2
arctan(-?v3)
Period = pi - Amplitude = 2 - Horizontal Shift 3/2 left
1
-1
45. 2p/3
y'(1/8)=66
1
100/3
arcsec(-2)
46. tan 11p/6
arctan(v3)
-v3/3
arctan 0
Period = pi - Amplitude = 3 - Vertical Shift up 1
47. y=2sin(2x)+3
Period = pi - Amplitude = 2 - Vertical Shift up 3
arcsec(v2)
1
U
48. tan 7p/6
arctan(?v3)
no solution
-v2/2
v3/3
49. sin p/4
1
2
-v2/2
v2/2
50. cos 0
1
arctan(-?v3)
-1
1/2