Test your basic knowledge |

GRE Math: Word Problems 1 And 2 Unknowns

Subjects : gre, math

Instructions:

Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. the sum of three even consecutive integers
y+y+2+y+4=3y+6
36 inches - 1 yard
5x+10
Product - times - of - double (x2) - triple (x3)

2. 4 pecks (dry measure)
1 bushel (dry measure)
36 inches - 1 yard
1 gallon
Difference

3. equal
1 quart
Is - am - are - was - wer - the same as - equal to
1 pound
x+x+1+x+2 = 3x+3

4. 2000 pounds
1 gallon
4y+12
1 cup
1 ton

5. 8 ounces
1 cup
1 quart
36 inches - 1 yard
1 mile

6. 8 quarts (dry measure)
1 peck (dry measure)
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 ton
1 quart (dry measure)

7. interest
3/5
1 cup
The amount the principal increases by
Product - times - of - double (x2) - triple (x3)

8. 5280 feet
Product - times - of - double (x2) - triple (x3)
Sum - plus - more than - increase - increase by
1 bushel (dry measure)
1 mile

9. 2 cups
1 pint
Sum of principal and interest
36 inches - 1 yard
quotient - divided by

10. the sum of four even consecutive integers
The amount the principal increases by
1 kg
1 mile
4y+12

11. division
quotient - divided by
Is - am - are - was - wer - the same as - equal to
1 mile
1 quart (dry measure)

12. multiplication
Interest (I)=Principal (P)annual rate (R) time in years (T)
4x+6
4y+12
Product - times - of - double (x2) - triple (x3)

13. the ratio of three to five
4x+6
1 gallon
1 foot
3/5

14. 1000 liters in ? kg
1 kiloliter
Initial deposit
5x+10
1 cup

15. subtraction
1 quart (dry measure)
1 gallon
4y+12
Difference

16. principal
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
4y+12
4x+6
Initial deposit

17. simple interest
1 peck (dry measure)
Difference
Interest (I)=Principal (P)annual rate (R) time in years (T)
The amount the principal increases by

18. 4 quarts
1 pound
Is - am - are - was - wer - the same as - equal to
1 gallon
4y+12

19. the sum of three consecutive integers
1 kiloliter
5x+10
x+x+1+x+2 = 3x+3
1 gallon

20. final amount
36 inches - 1 yard
Sum of principal and interest
1 cup
Initial deposit

21. the sum of five consecutive integers
1 ton
3/5
1 kg
5x+10

22. compound interest
1 ton
1 cup
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 mile

23. the sum of four consecutive integers
Initial deposit
3/5
4x+6
Sum - plus - more than - increase - increase by

24. 1000 grams
1 kg
36 inches - 1 yard
1 kiloliter
1 quart (dry measure)

25. 12 inches
1 pound
36 inches - 1 yard
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 foot

26. addition
4x+6
1 cup
Sum - plus - more than - increase - increase by
Difference

27. 2 pints
Sum of principal and interest
1 quart
1 cup
1 mile

28. 3 feet
1 cup
3/5
1 foot
36 inches - 1 yard

29. 2 pints (dry measure)
Sum of principal and interest
1 mile
1 quart (dry measure)
1 bushel (dry measure)

30. 16 ounces (weight)
1 pound
Sum of principal and interest
1 bushel (dry measure)
4x+6