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GRE Math: Word Problems 1 And 2 Unknowns

Subjects : gre, math

Instructions:

Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. simple interest
5x+10
1 gallon
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 mile

2. interest
1 gallon
1 quart
The amount the principal increases by
1 mile

3. the ratio of three to five
1 ton
3/5
1 mile
Sum - plus - more than - increase - increase by

4. addition
1 cup
5x+10
Product - times - of - double (x2) - triple (x3)
Sum - plus - more than - increase - increase by

5. 2 pints
36 inches - 1 yard
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 quart
Sum - plus - more than - increase - increase by

6. division
4y+12
1 mile
1 cup
quotient - divided by

7. 2 pints (dry measure)
1 kiloliter
1 pint
1 quart (dry measure)
1 foot

8. 1000 liters in ? kg
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 kiloliter
1 cup
Initial deposit

9. subtraction
x+x+1+x+2 = 3x+3
1 peck (dry measure)
1 ton
Difference

10. 2000 pounds
quotient - divided by
5x+10
36 inches - 1 yard
1 ton

11. 8 quarts (dry measure)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 peck (dry measure)
1 kiloliter
1 kg

12. the sum of three even consecutive integers
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
y+y+2+y+4=3y+6
quotient - divided by
3/5

13. principal
Interest (I)=Principal (P)annual rate (R) time in years (T)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
4x+6
Initial deposit

14. 4 quarts
3/5
1 gallon
1 quart
1 quart (dry measure)

15. 2 cups
1 ton
1 kiloliter
1 quart (dry measure)
1 pint

16. compound interest
The amount the principal increases by
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
x+x+1+x+2 = 3x+3
1 pound

17. 1000 grams
1 kg
1 cup
4y+12
Sum of principal and interest

18. 3 feet
36 inches - 1 yard
3/5
1 quart (dry measure)
Sum - plus - more than - increase - increase by

19. the sum of four even consecutive integers
Sum of principal and interest
3/5
1 peck (dry measure)
4y+12

20. the sum of five consecutive integers
Difference
5x+10
4x+6
1 foot

21. 16 ounces (weight)
1 kg
1 pound
Is - am - are - was - wer - the same as - equal to
The amount the principal increases by

22. the sum of four consecutive integers
Difference
Interest (I)=Principal (P)annual rate (R) time in years (T)
4x+6
The amount the principal increases by

23. 8 ounces
1 cup
1 peck (dry measure)
Sum of principal and interest
Product - times - of - double (x2) - triple (x3)

24. 5280 feet
5x+10
1 mile
1 quart (dry measure)
4x+6

25. equal
1 peck (dry measure)
Difference
Is - am - are - was - wer - the same as - equal to
Product - times - of - double (x2) - triple (x3)

26. final amount
5x+10
4x+6
Difference
Sum of principal and interest

27. 12 inches
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 foot
Sum of principal and interest
quotient - divided by

28. multiplication
4x+6
Product - times - of - double (x2) - triple (x3)
1 kg
Difference

29. 4 pecks (dry measure)
1 bushel (dry measure)
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 quart (dry measure)
5x+10

30. the sum of three consecutive integers
1 kg
4y+12
x+x+1+x+2 = 3x+3
The amount the principal increases by