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Test your basic knowledge |
GRE Math: Word Problems 1 And 2 Unknowns
Start Test
Study First
Subjects
:
gre
,
math
Instructions:
Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. interest
The amount the principal increases by
Product - times - of - double (x2) - triple (x3)
x+x+1+x+2 = 3x+3
1 bushel (dry measure)
2. 1000 grams
1 kg
Is - am - are - was - wer - the same as - equal to
Product - times - of - double (x2) - triple (x3)
1 gallon
3. 3 feet
The amount the principal increases by
5x+10
Product - times - of - double (x2) - triple (x3)
36 inches - 1 yard
4. compound interest
1 mile
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
4x+6
The amount the principal increases by
5. the sum of three consecutive integers
Sum - plus - more than - increase - increase by
1 kiloliter
1 kg
x+x+1+x+2 = 3x+3
6. principal
Product - times - of - double (x2) - triple (x3)
Initial deposit
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
Sum - plus - more than - increase - increase by
7. 2 cups
1 pint
1 quart
Sum of principal and interest
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
8. 2 pints (dry measure)
1 quart (dry measure)
1 bushel (dry measure)
Interest (I)=Principal (P)annual rate (R) time in years (T)
Initial deposit
9. simple interest
1 gallon
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 quart
x+x+1+x+2 = 3x+3
10. addition
1 bushel (dry measure)
Sum - plus - more than - increase - increase by
1 kiloliter
Sum of principal and interest
11. the ratio of three to five
3/5
1 kiloliter
x+x+1+x+2 = 3x+3
1 quart (dry measure)
12. subtraction
1 mile
4y+12
Difference
1 quart (dry measure)
13. division
x+x+1+x+2 = 3x+3
Initial deposit
quotient - divided by
1 bushel (dry measure)
14. 16 ounces (weight)
1 mile
1 pound
5x+10
1 pint
15. equal
x+x+1+x+2 = 3x+3
Is - am - are - was - wer - the same as - equal to
1 gallon
1 mile
16. 8 ounces
1 ton
Initial deposit
1 cup
1 kg
17. 1000 liters in ? kg
x+x+1+x+2 = 3x+3
1 kiloliter
Sum of principal and interest
1 bushel (dry measure)
18. 2 pints
Difference
Sum - plus - more than - increase - increase by
5x+10
1 quart
19. 8 quarts (dry measure)
1 peck (dry measure)
y+y+2+y+4=3y+6
quotient - divided by
1 foot
20. the sum of four even consecutive integers
The amount the principal increases by
1 cup
1 ton
4y+12
21. the sum of three even consecutive integers
3/5
y+y+2+y+4=3y+6
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 gallon
22. final amount
1 kg
Sum of principal and interest
y+y+2+y+4=3y+6
1 peck (dry measure)
23. 5280 feet
1 ton
1 mile
1 gallon
1 quart (dry measure)
24. multiplication
5x+10
36 inches - 1 yard
The amount the principal increases by
Product - times - of - double (x2) - triple (x3)
25. the sum of five consecutive integers
Difference
1 ton
5x+10
y+y+2+y+4=3y+6
26. the sum of four consecutive integers
Sum - plus - more than - increase - increase by
The amount the principal increases by
Initial deposit
4x+6
27. 2000 pounds
1 mile
1 foot
1 gallon
1 ton
28. 12 inches
1 foot
Product - times - of - double (x2) - triple (x3)
3/5
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
29. 4 pecks (dry measure)
36 inches - 1 yard
1 bushel (dry measure)
y+y+2+y+4=3y+6
1 peck (dry measure)
30. 4 quarts
5x+10
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 gallon
Is - am - are - was - wer - the same as - equal to