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GRE Math: Word Problems 1 And 2 Unknowns

Subjects : gre, math

Instructions:

Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. compound interest
1 pint
The amount the principal increases by
1 quart
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

2. division
4y+12
quotient - divided by
Initial deposit
y+y+2+y+4=3y+6

3. 5280 feet
1 kiloliter
Interest (I)=Principal (P)annual rate (R) time in years (T)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 mile

4. 4 quarts
1 pound
1 gallon
1 bushel (dry measure)
Difference

5. 2 cups
Is - am - are - was - wer - the same as - equal to
1 pint
quotient - divided by
x+x+1+x+2 = 3x+3

6. multiplication
Product - times - of - double (x2) - triple (x3)
1 foot
Sum of principal and interest
4x+6

7. the sum of three consecutive integers
1 pint
x+x+1+x+2 = 3x+3
Sum - plus - more than - increase - increase by
Product - times - of - double (x2) - triple (x3)

8. 1000 liters in ? kg
Sum of principal and interest
Difference
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 kiloliter

9. the ratio of three to five
1 gallon
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
Sum - plus - more than - increase - increase by
3/5

10. interest
Sum - plus - more than - increase - increase by
quotient - divided by
The amount the principal increases by
1 bushel (dry measure)

11. 2 pints (dry measure)
1 quart (dry measure)
x+x+1+x+2 = 3x+3
Sum of principal and interest
1 quart

12. subtraction
4y+12
Sum of principal and interest
1 kg
Difference

13. the sum of four even consecutive integers
Is - am - are - was - wer - the same as - equal to
4y+12
1 gallon
1 quart (dry measure)

14. equal
1 foot
Is - am - are - was - wer - the same as - equal to
3/5
4y+12

15. final amount
Sum of principal and interest
1 gallon
4y+12
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

16. 16 ounces (weight)
1 gallon
1 ton
quotient - divided by
1 pound

17. the sum of five consecutive integers
1 quart
1 pint
Interest (I)=Principal (P)annual rate (R) time in years (T)
5x+10

18. 4 pecks (dry measure)
1 bushel (dry measure)
1 kg
1 cup
Initial deposit

19. addition
Sum of principal and interest
1 quart (dry measure)
Is - am - are - was - wer - the same as - equal to
Sum - plus - more than - increase - increase by

20. 8 ounces
1 foot
1 cup
1 quart (dry measure)
1 kiloliter

21. the sum of three even consecutive integers
1 cup
1 peck (dry measure)
Sum - plus - more than - increase - increase by
y+y+2+y+4=3y+6

22. simple interest
Interest (I)=Principal (P)annual rate (R) time in years (T)
3/5
5x+10
The amount the principal increases by

23. 12 inches
The amount the principal increases by
y+y+2+y+4=3y+6
1 foot
1 bushel (dry measure)

24. 8 quarts (dry measure)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 quart
1 gallon
1 peck (dry measure)

25. principal
x+x+1+x+2 = 3x+3
1 pound
Initial deposit
quotient - divided by

26. the sum of four consecutive integers
4x+6
Is - am - are - was - wer - the same as - equal to
36 inches - 1 yard
Initial deposit

27. 2000 pounds
36 inches - 1 yard
4x+6
1 pint
1 ton

28. 1000 grams
The amount the principal increases by
Sum of principal and interest
Initial deposit
1 kg

29. 3 feet
Sum of principal and interest
1 foot
1 kg
36 inches - 1 yard

30. 2 pints
4y+12
1 quart
3/5
1 foot