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GRE Math: Word Problems 1 And 2 Unknowns

Subjects : gre, math

Instructions:

Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. subtraction
4x+6
1 bushel (dry measure)
1 pint
Difference

2. principal
Initial deposit
1 pound
5x+10
1 quart

3. the sum of four consecutive integers
Initial deposit
y+y+2+y+4=3y+6
4x+6
1 cup

4. multiplication
1 pound
Difference
Product - times - of - double (x2) - triple (x3)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

5. the sum of three consecutive integers
1 pound
1 gallon
Is - am - are - was - wer - the same as - equal to
x+x+1+x+2 = 3x+3

6. 4 quarts
1 quart (dry measure)
36 inches - 1 yard
1 bushel (dry measure)
1 gallon

7. the ratio of three to five
5x+10
3/5
4x+6
1 pound

8. 2000 pounds
1 ton
1 pint
1 kiloliter
1 foot

9. 1000 liters in ? kg
1 kiloliter
5x+10
1 pound
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

10. equal
Difference
1 mile
Is - am - are - was - wer - the same as - equal to
Sum - plus - more than - increase - increase by

11. the sum of four even consecutive integers
4y+12
1 pint
36 inches - 1 yard
1 quart

12. division
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 cup
1 pound
quotient - divided by

13. 2 pints (dry measure)
Product - times - of - double (x2) - triple (x3)
1 pint
5x+10
1 quart (dry measure)

14. 5280 feet
5x+10
1 mile
Product - times - of - double (x2) - triple (x3)
1 bushel (dry measure)

15. compound interest
1 quart
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
3/5
1 peck (dry measure)

16. the sum of three even consecutive integers
y+y+2+y+4=3y+6
36 inches - 1 yard
4y+12
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

17. 2 pints
1 foot
1 quart
4y+12
3/5

18. interest
Initial deposit
3/5
1 cup
The amount the principal increases by

19. 16 ounces (weight)
1 kg
1 quart (dry measure)
Is - am - are - was - wer - the same as - equal to
1 pound

20. 1000 grams
Sum of principal and interest
1 kg
1 mile
1 gallon

21. simple interest
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 mile
Sum of principal and interest
1 bushel (dry measure)

22. addition
Sum - plus - more than - increase - increase by
1 quart (dry measure)
4y+12
1 peck (dry measure)

23. 8 ounces
1 gallon
1 cup
x+x+1+x+2 = 3x+3
Is - am - are - was - wer - the same as - equal to

24. 12 inches
1 foot
Sum of principal and interest
quotient - divided by
Sum - plus - more than - increase - increase by

25. 4 pecks (dry measure)
Sum - plus - more than - increase - increase by
quotient - divided by
1 bushel (dry measure)
4y+12

26. the sum of five consecutive integers
5x+10
1 pound
1 quart
4x+6

27. 3 feet
1 ton
Difference
36 inches - 1 yard
Is - am - are - was - wer - the same as - equal to

28. 2 cups
1 ton
1 pound
Sum - plus - more than - increase - increase by
1 pint

29. 8 quarts (dry measure)
1 foot
1 peck (dry measure)
1 pound
quotient - divided by

30. final amount
1 kiloliter
Initial deposit
Sum of principal and interest
1 mile