Test your basic knowledge |

GRE Math: Word Problems 1 And 2 Unknowns

Subjects : gre, math

Instructions:

Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. principal
Initial deposit
1 foot
4y+12
1 pound

2. the ratio of three to five
1 pint
3/5
4y+12
1 ton

3. equal
Is - am - are - was - wer - the same as - equal to
1 quart (dry measure)
4y+12
The amount the principal increases by

4. the sum of three consecutive integers
1 ton
1 kg
1 quart (dry measure)
x+x+1+x+2 = 3x+3

5. subtraction
Difference
36 inches - 1 yard
The amount the principal increases by
1 peck (dry measure)

6. the sum of four consecutive integers
Interest (I)=Principal (P)annual rate (R) time in years (T)
4x+6
Sum - plus - more than - increase - increase by
1 pint

7. addition
1 cup
Is - am - are - was - wer - the same as - equal to
Sum - plus - more than - increase - increase by
1 peck (dry measure)

8. the sum of five consecutive integers
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 cup
5x+10
1 quart (dry measure)

9. 1000 grams
The amount the principal increases by
y+y+2+y+4=3y+6
x+x+1+x+2 = 3x+3
1 kg

10. final amount
4x+6
1 mile
1 ton
Sum of principal and interest

11. 8 quarts (dry measure)
The amount the principal increases by
1 quart
1 pound
1 peck (dry measure)

12. simple interest
1 kg
1 quart (dry measure)
Sum - plus - more than - increase - increase by
Interest (I)=Principal (P)annual rate (R) time in years (T)

13. 2 pints
1 kg
1 quart (dry measure)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 quart

14. 1000 liters in ? kg
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
1 kiloliter
1 kg
4y+12

15. the sum of three even consecutive integers
1 kiloliter
Is - am - are - was - wer - the same as - equal to
y+y+2+y+4=3y+6
4y+12

16. division
3/5
quotient - divided by
1 gallon
x+x+1+x+2 = 3x+3

17. 2 pints (dry measure)
1 pound
1 gallon
1 quart (dry measure)
3/5

18. 5280 feet
1 mile
The amount the principal increases by
Difference
Product - times - of - double (x2) - triple (x3)

19. the sum of four even consecutive integers
4y+12
36 inches - 1 yard
Sum - plus - more than - increase - increase by
Product - times - of - double (x2) - triple (x3)

20. compound interest
36 inches - 1 yard
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
Is - am - are - was - wer - the same as - equal to
quotient - divided by

21. 4 quarts
1 gallon
1 quart
4x+6
36 inches - 1 yard

22. 8 ounces
1 cup
3/5
1 foot
Interest (I)=Principal (P)annual rate (R) time in years (T)

23. 2000 pounds
Sum - plus - more than - increase - increase by
1 mile
Is - am - are - was - wer - the same as - equal to
1 ton

24. 2 cups
The amount the principal increases by
1 mile
1 pint
quotient - divided by

25. 4 pecks (dry measure)
1 ton
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 bushel (dry measure)
Difference

26. 3 feet
4x+6
36 inches - 1 yard
Difference
1 peck (dry measure)

27. 16 ounces (weight)
1 pound
The amount the principal increases by
4y+12
1 gallon

28. interest
1 cup
The amount the principal increases by
1 ton
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

29. 12 inches
36 inches - 1 yard
Difference
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 foot

30. multiplication
Product - times - of - double (x2) - triple (x3)
Difference
1 pint
1 quart