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GRE Math: Word Problems 1 And 2 Unknowns

Subjects : gre, math

Instructions:

Answer 30 questions in 15 minutes.
If you are not ready to take this test, you can study here.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.

This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.

1. the sum of four consecutive integers
x+x+1+x+2 = 3x+3
1 mile
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
4x+6

2. multiplication
Product - times - of - double (x2) - triple (x3)
1 quart
1 kg
y+y+2+y+4=3y+6

3. 2 cups
4x+6
1 pint
4y+12
1 mile

4. 2000 pounds
4y+12
1 kiloliter
1 ton
The amount the principal increases by

5. 16 ounces (weight)
Sum - plus - more than - increase - increase by
1 pound
4y+12
5x+10

6. division
quotient - divided by
Difference
1 foot
1 peck (dry measure)

7. 1000 grams
Sum of principal and interest
4y+12
1 quart (dry measure)
1 kg

8. 4 pecks (dry measure)
1 quart (dry measure)
1 pound
4x+6
1 bushel (dry measure)

9. 4 quarts
1 gallon
The amount the principal increases by
Initial deposit
1 foot

10. 5280 feet
1 foot
Product - times - of - double (x2) - triple (x3)
1 mile
Is - am - are - was - wer - the same as - equal to

11. final amount
The amount the principal increases by
3/5
Sum of principal and interest
x+x+1+x+2 = 3x+3

12. the sum of three even consecutive integers
y+y+2+y+4=3y+6
1 ton
1 kiloliter
1 bushel (dry measure)

13. the ratio of three to five
1 kiloliter
1 quart
3/5
1 foot

14. 8 ounces
1 ton
1 pint
1 cup
1 kiloliter

15. compound interest
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
3/5
The amount the principal increases by
1 quart (dry measure)

16. 2 pints (dry measure)
1 quart (dry measure)
1 pound
Product - times - of - double (x2) - triple (x3)
1 mile

17. simple interest
1 kg
4y+12
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 bushel (dry measure)

18. 1000 liters in ? kg
1 kiloliter
4x+6
The amount the principal increases by
1 cup

19. addition
Sum - plus - more than - increase - increase by
Initial deposit
1 cup
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

20. equal
Is - am - are - was - wer - the same as - equal to
36 inches - 1 yard
1 quart
Sum - plus - more than - increase - increase by

21. subtraction
1 quart
Difference
Product - times - of - double (x2) - triple (x3)
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt

22. the sum of five consecutive integers
5x+10
1 kiloliter
x+x+1+x+2 = 3x+3
quotient - divided by

23. 8 quarts (dry measure)
4y+12
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 cup
1 peck (dry measure)

24. interest
The amount the principal increases by
1 foot
1 bushel (dry measure)
4y+12

25. 3 feet
y+y+2+y+4=3y+6
1 gallon
36 inches - 1 yard
Difference

26. the sum of four even consecutive integers
3/5
Is - am - are - was - wer - the same as - equal to
4y+12
1 peck (dry measure)

27. 2 pints
1 quart
quotient - divided by
Interest (I)=Principal (P)annual rate (R) time in years (T)
1 quart (dry measure)

28. principal
Difference
quotient - divided by
1 quart (dry measure)
Initial deposit

29. the sum of three consecutive integers
1 ton
Compound Interest (A)=Principal (P)(1+rate (R)/#compunds (n))^nt
x+x+1+x+2 = 3x+3
Interest (I)=Principal (P)annual rate (R) time in years (T)

30. 12 inches
1 ton
1 foot
1 pound
1 kiloliter