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Test your basic knowledge |
Advanced Food Processing
Start Test
Study First
Subjects
:
industries
,
engineering
Instructions:
Answer 33 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Is also used in limited extent in food irradiation.
Cesium 137
Penetration Depth
Gamma rays
Food Irradiation
2. High frequency & short wave length
Dielectric Loss
Penetration Depth
Gamma rays
0.005 KGY
3. -the more complex the biological system is the less amount of IR required to induce changes
When issued - approval includes
True
Food Irradiation
Cesium 137
4. Determines the affinity of a food system to absorb microwaves
100 KGY dose
5 KGY
Dielectric Constant
Gamma rays
5. What is the half life of Cobalt 60?
Chemical and physical
true
5 Years
UV in the range of 200-280 nm
6. Gamma rays have high penetration capability
true
Microwaves
0.12 KGY
0.005 KGY
7. Determines how far the MWs penetrate into the food and it is affected by the above two parameters plus others
Penetration Depth
The Electromagnetic Spectrum (EMS)
Gamma rays
true
8. The food category - the purpose of irradiation - and the dose permitted in KGY
Radiation Absorbed Dose (RAD)
Radio waves
When issued - approval includes
Chemical and physical
9. 1000 GY
Food Irradiation
1 KGY
0.12 KGY
Chemical and physical
10. Pasteurization of herbs and spices
0.1-1 KGY)
Cobalt 60
2-5 KGY
Radiation Absorbed Dose (RAD)
11. Which waves vary in frequency and are closer to Radio waves frequencies
Cesium 137
2-5 KGY
Microwaves
Gamma rays
12. Made into an unstable isotope by neutron bombardment
Chemical and physical
Cesium 137
0.2-5 KGY
Cobalt 59
13. Dose required to kill virus?
100 KGY dose
Microwaves
1 GY
True
14. Food treated with ionizing radiation (IR) is said to be
Penetration Depth
gamma rays
irradiated
Cobalt 59
15. Low frequency & long wave length
irradiated
When issued - approval includes
100 KGY dose
Radio waves
16. Dose required to kill a man
Cesium 137
0.1-1 KGY)
0.005 KGY
Radiation Absorbed Dose (RAD)
17. The common source of energy in food irradiation
0.2-5 KGY
Microwaves
Cobalt 60
50 KGY
18. Direct Effect- a bullet-like effect with high energy particles impacting the vital parts of the cell
Penetration Depth
Gamma rays
irradiated
First mechanisms by which IR achieves biological stability in food
19. Dose required to kill yeast and mold?
5 KGY
Dielectric Constant
Chemical and physical
Second mechanisms by which IR achieves biological stability in food
20. Dose required to kill bacterial spores?
Radiation Absorbed Dose (RAD)
Chemical and physical
50 KGY
0.005 KGY
21. The quantity of radiation that results in the absorption of 100 ergs per gram of food
irradiated
Dielectric Constant
Radiation Absorbed Dose (RAD)
When issued - approval includes
22. 100 RAD
Radio waves
5 KGY
Cobalt 60
1 GY
23. Describes a continuous range of radiation energy having an electric and a magnetic component
The Electromagnetic Spectrum (EMS)
Chemical and physical
1 GY
Cobalt 60
24. Traditional unit of measuring the amount of energy absorbed by food
Radio waves
0.005 KGY
5 KGY
Radiation Absorbed Dose (RAD)
25. Sprouting inhibition and
UV in the range of 200-280 nm
0.1-1 KGY)
true
1 GY
26. Determines the amount of heat generated from the absorbed energy
Cobalt 60
Chemical and physical
Dielectric Loss
0.2-5 KGY
27. Indirect Effect- ionization of molecules that produces ion pairs (by knocking off an electron) and free radicals (by breaking bonds) result in chemical reactions that interrupt biological functions
The Electromagnetic Spectrum (EMS)
Second mechanisms by which IR achieves biological stability in food
5 KGY
Dielectric Loss
28. These rays have no penetration depth hence it will only achieve surface inactivation of microorganisms
irradiated
UV in the range of 200-280 nm
Chemical and physical
0.1-1 KGY)
29. Killing insects and eggs
0.2-5 KGY
Food Irradiation
The Electromagnetic Spectrum (EMS)
1 GY
30. What kind of rays does Cobalt 60 emit?
5 KGY
0.2-5 KGY
Radio waves
gamma rays
31. Utilizing (IR) to achieve biological stability of food by inhibiting or minimizing spoilage reactions
0.12 KGY
irradiated
Food Irradiation
Cobalt 60
32. What changes take place when energy is applied?
Penetration Depth
Chemical and physical
When issued - approval includes
Cobalt 59
33. Dose required to kill insects?
5 KGY
UV in the range of 200-280 nm
irradiated
0.12 KGY