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Test your basic knowledge |
Advanced Food Processing
Start Test
Study First
Subjects
:
industries
,
engineering
Instructions:
Answer 33 questions in 15 minutes.
If you are not ready to take this test, you can
study here
.
Match each statement with the correct term.
Don't refresh. All questions and answers are randomly picked and ordered every time you load a test.
This is a study tool. The 3 wrong answers for each question are randomly chosen from answers to other questions. So, you might find at times the answers obvious, but you will see it re-enforces your understanding as you take the test each time.
1. Determines how far the MWs penetrate into the food and it is affected by the above two parameters plus others
Penetration Depth
0.1-1 KGY)
1 GY
50 KGY
2. 100 RAD
1 GY
5 Years
Second mechanisms by which IR achieves biological stability in food
Dielectric Constant
3. Dose required to kill insects?
0.2-5 KGY
Cobalt 59
0.12 KGY
Gamma rays
4. Is also used in limited extent in food irradiation.
Radiation Absorbed Dose (RAD)
Radio waves
Food Irradiation
Cesium 137
5. Food treated with ionizing radiation (IR) is said to be
Gamma rays
irradiated
2-5 KGY
50 KGY
6. These rays have no penetration depth hence it will only achieve surface inactivation of microorganisms
100 KGY dose
0.2-5 KGY
True
UV in the range of 200-280 nm
7. What kind of rays does Cobalt 60 emit?
gamma rays
Penetration Depth
Radiation Absorbed Dose (RAD)
1 GY
8. Dose required to kill a man
Cobalt 59
0.005 KGY
0.12 KGY
UV in the range of 200-280 nm
9. Describes a continuous range of radiation energy having an electric and a magnetic component
2-5 KGY
The Electromagnetic Spectrum (EMS)
Radio waves
0.2-5 KGY
10. The food category - the purpose of irradiation - and the dose permitted in KGY
The Electromagnetic Spectrum (EMS)
Gamma rays
When issued - approval includes
Radiation Absorbed Dose (RAD)
11. Indirect Effect- ionization of molecules that produces ion pairs (by knocking off an electron) and free radicals (by breaking bonds) result in chemical reactions that interrupt biological functions
1 KGY
0.005 KGY
Second mechanisms by which IR achieves biological stability in food
UV in the range of 200-280 nm
12. Pasteurization of herbs and spices
First mechanisms by which IR achieves biological stability in food
2-5 KGY
1 GY
0.005 KGY
13. Direct Effect- a bullet-like effect with high energy particles impacting the vital parts of the cell
1 GY
First mechanisms by which IR achieves biological stability in food
Microwaves
1 KGY
14. Dose required to kill bacterial spores?
50 KGY
true
Cesium 137
2-5 KGY
15. 1000 GY
50 KGY
UV in the range of 200-280 nm
1 KGY
Dielectric Loss
16. Killing insects and eggs
true
First mechanisms by which IR achieves biological stability in food
Gamma rays
0.2-5 KGY
17. Low frequency & long wave length
50 KGY
0.005 KGY
Radio waves
Dielectric Constant
18. -the more complex the biological system is the less amount of IR required to induce changes
True
Microwaves
5 KGY
Dielectric Constant
19. Dose required to kill yeast and mold?
2-5 KGY
Cobalt 60
5 KGY
Cobalt 59
20. High frequency & short wave length
Gamma rays
When issued - approval includes
true
0.12 KGY
21. Utilizing (IR) to achieve biological stability of food by inhibiting or minimizing spoilage reactions
Food Irradiation
100 KGY dose
Penetration Depth
0.005 KGY
22. Sprouting inhibition and
1 KGY
0.1-1 KGY)
true
Cobalt 59
23. Gamma rays have high penetration capability
Radio waves
Dielectric Loss
When issued - approval includes
true
24. What changes take place when energy is applied?
Radio waves
Chemical and physical
UV in the range of 200-280 nm
gamma rays
25. Which waves vary in frequency and are closer to Radio waves frequencies
First mechanisms by which IR achieves biological stability in food
True
Cobalt 60
Microwaves
26. Traditional unit of measuring the amount of energy absorbed by food
true
Cesium 137
0.1-1 KGY)
Radiation Absorbed Dose (RAD)
27. What is the half life of Cobalt 60?
5 Years
1 GY
0.2-5 KGY
irradiated
28. Dose required to kill virus?
0.005 KGY
true
100 KGY dose
5 KGY
29. Determines the affinity of a food system to absorb microwaves
Dielectric Constant
Microwaves
Dielectric Loss
Chemical and physical
30. The quantity of radiation that results in the absorption of 100 ergs per gram of food
irradiated
Radiation Absorbed Dose (RAD)
Cobalt 60
Cesium 137
31. Determines the amount of heat generated from the absorbed energy
5 KGY
0.1-1 KGY)
Dielectric Loss
Cesium 137
32. Made into an unstable isotope by neutron bombardment
Second mechanisms by which IR achieves biological stability in food
Cobalt 59
5 Years
0.005 KGY
33. The common source of energy in food irradiation
0.12 KGY
Cobalt 60
Food Irradiation
Cobalt 59